Where should you look to determine the zeros of a quadratic function?
X-intercepts
(2x - 13)(x + 8) = 0
X = 13/2 and x = -8
B2-4AC = 82-4(5)(2) = 44
2x2 = 200
x = 10 and -10
Does 2x2 - 9x + 8 have a maximum or a minimum? How do you know?
Minimum because the parabola opens up
A quadratic function has no solutions. Draw what this could look like.
Solve by factoring: x2 + 2x - 35 = 0
(-7,0) & (5,0)
determine a,b,&c
2x2 + 9x - 5 = 3x - 17
A = 2
B = 6
C = 12
(x-3)2 + 9 = 25
x = 7 or -1
Find the vertex of 5(x + 19)2 + 17
(-19, 17)
Plot 3(x-4)2 - 12 in your graphing calculator. Determine the solutions.
(2,0) & (6,0)
2x2 + 9x + 10 = 0
x = -2 and x = -5/2
Simplify sqrt(147)
147 = 3*7*7 so sqrt (147) = 7sqrt(3)
2x2 + 19 = 29
x = +- sqrt (5)
Find the interval of increase for
3(x - 1)2 + 7
(1, positive infinity) the graph opens up. Label negative infinity U positive infinity and circle the x-value of the vertex.
Solve 2x2 + 4x - 16 = 0 by graphing.
(-4,0) & (2,0)
2x2 + 3x + 8 = x2 + 48
x = -8 and x = 5
Solve using the quadratic formula:
x2 + 8x + 1 = 0
x = [-8 +- sqrt(60) ] / 2
x = [-8 +- 2sqrt(15) ] / 2
x = -4 +- sqrt(15)
4(x - 1)2 = 24
x = 1 +- sqrt (6)
What is the range of -2(x + 6)2 + 5
y <= 5
Graph opens down with a max at y = 5
Solve the equation by graphing.
x2 + 10x + 25 = 0
(-5,0)
3x2 + 4x - 7 = -x2 - 8x
Solve using quadratic formula:
x2 + 9x - 1 = 3x + 12
A = 1 B = 6 C = -13
x = [ -6 +- sqrt (88) ] / 2
x = -3 +- sqrt (22)
(3x + 1)2 - 7 = 176
x = 4 and -14/3
Find the vertex of 2x2 + 16x + 37
-b/2a
(-4,5)