1
2
3
4
5
100

No 3

Because you can plug in any value of "x" and the domain of a function represent the admissible values of "x".

100
No 4

Because the parabolas we studied have a vertex, it goes from that vertex either upwards or downwards. The range of a function represent the possible values for "y".

100

No 2

The sign of the coefficient "a". If a>0 it opens upwards, if a<0 it opens downwards.

100

No 1

To account for two possible solutions.

100

No 6

(x-1)(x+44)

200

No 6

(4x+3)2

200

No 9

x=\frac{-9-\sqrt{113}}{8}

x=\frac{-9+\sqrt{113}}{8}

200

No 10

\frac{1+\sqrt{5}}{2}

\frac{1-\sqrt{5}}{2}


200

No 7

x=3/4, x=-17/3

200

No 8

x=-78/5, x=13/34

300

No 13

Domain=All numbers. Range [0,\infty)

300

No 14

Domain=All numbers. Range [-33/4,\infty]

300

No 11

Vertex: (-9/8, -113/16)

300

No 15

 The vertex at x=30 gives the number of crafts which gives the maximum profit.

300

No 12

Vertex: (1/2, -5/4)

400

No 16

The vertex at t=19 gives the time at which the maximum height is reached.

400

What technique is used to prove the quadratic formula?

Completing the square.

400

What happens to the quadratic formula when the quadratic equation in question has no solutions?

The value inside the square root is negative.

400

What happens to the quadratic formula when the quadratic equation in question has one solutions?

The value inside the square root is zero.

400

What happens to the quadratic formula when the quadratic equation in question has two solutions?

The value inside the square root is positive.