T1
T2
T3
T4
T5
100
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
8/15 (
A's 1 day's work =1;15
B's 1 day's work =1;20
(A + B)'s 1 day's work =
1+1
=7.152060
(A + B)'s 4 day's work =7x 4=7.6015
Therefore, Remaining work =1 -7=8.1515
)
A's 1 day's work =1;15
B's 1 day's work =1;20
(A + B)'s 1 day's work =
1+1=7.152060(A + B)'s 4 day's work =
7x 4=7.6015Therefore, Remaining work =
1 -7=8.1515)
100
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
9 3/5daysExplanation:
(A + B + C)'s 1 day's work =1,4
A's 1 day's work =1,16
B's 1 day's work =1.12
C's 1 day's work =1-1+1=1-7=5.4161244848
So, C alone can do the work in48= 93days.55
(A + B + C)'s 1 day's work =1,4
A's 1 day's work =1,16
B's 1 day's work =1.12
C's 1 day's work =1-1+1=1-7=5.4161244848So, C alone can do the work in48= 93days.55
100
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
15 days Explanation:
A's 2 day's work =1x 2=1.2010
(A + B + C)'s 1 day's work =1+1+1=6=1.2030606010
Work done in 3 days =1+1=1.10105
Now,1work is done in 3 days.5
A's 2 day's work =
1x 2=1.2010(A + B + C)'s 1 day's work =
1+1+1=6=1.2030606010Work done in 3 days =
1+1=1.10105Now,1work is done in 3 days.5
Whole work will be done in (3 x 5) = 15 days.
100
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
22 1/2 days Explanation:Ratio of times taken by A and B = 1 : 3.The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes3x 60= 90 days.2
So, A takes 30 days to do the work.
A's 1 day's work =130
B's 1 day's work =190
(A + B)'s 1 day's work =1+1=4=230909045
A and B together can do the work in45= 221days.22
If difference of time is 60 days, B takes
3x 60= 90 days.2So, A takes 30 days to do the work.
A's 1 day's work =130
B's 1 day's work =190
(A + B)'s 1 day's work =
1+1=4=230909045 A and B together can do the work in45= 221days.22100
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Rs. 400 Explanation:
C's 1 day's work =1-1+1=1-7=1.36832424
A's wages : B's wages : C's wages =1:1:1= 4 : 3 : 1.6824
C's share (for 3 days) = Rs.3 x1x 3200= Rs. 400.24
C's 1 day's work =1-
1+1=1-7=1.36832424A's wages : B's wages : C's wages =1:1:1= 4 : 3 : 1.6824
C's share (for 3 days) = Rs.3 x1x 3200= Rs. 400.24200
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
4 days
Explanation:Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.Then, 6x + 8y =1and 26x + 48y =1.102
Solving these two equations, we get : x =1and y =1.100200
(15 men + 20 boy)'s 1 day's work =
15+20=1.1002004 15 men and 20 boys can do the work in 4 days.200
A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
12 hours Explanation:
A's 1 hour's work =1;4
(B + C)'s 1 hour's work =1;3
(A + C)'s 1 hour's work =1.2
(A + B + C)'s 1 hour's work =1+1=7.4312
B's 1 hour's work =7-1=1.12212
B alone will take 12 hours to do the work.
A's 1 hour's work =1;4
(B + C)'s 1 hour's work =1;3
(A + C)'s 1 hour's work =1.2
(A + B + C)'s 1 hour's work =
1+1=7.4312B's 1 hour's work =
7-1=1.12212 B alone will take 12 hours to do the work.200
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
25 days Explanation:
(A + B)'s 1 day's work =110
C's 1 day's work =150
(A + B + C)'s 1 day's work =1+1=6=3. .... (i)10505025
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) =325
A's 1 day's work =3.50
B's 1 day's work1-3=2=1.10505025
So, B alone could do the work in 25 days.
(A + B)'s 1 day's work =110
C's 1 day's work =150
(A + B + C)'s 1 day's work =
1+1=6=3. .... (i)10505025A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) =325
A's 1 day's work =3.50 B's 1 day's work1-3=2=1.10505025So, B alone could do the work in 25 days.
200
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
37
Explanation:
Whole work is done by A in20 x5= 25 days.4
Now,1 -4i.e.,1work is done by A and B in 3 days.55
Whole work will be done by A and B in (3 x 5) = 15 days.
A's 1 day's work =1, (A + B)'s 1 day's work =1.2515
B's 1 day's work =1-1=4=2.152515075
So, B alone would do the work in75= 371days.22
Explanation:Whole work is done by A in
20 x5= 25 days.4Now,
1 -4i.e.,1work is done by A and B in 3 days.55Whole work will be done by A and B in (3 x 5) = 15 days.
A's 1 day's work =1, (A + B)'s 1 day's work =1.2515
B's 1 day's work =1-1=4=2.152515075So, B alone would do the work in75= 371days.22
200
A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?
1:00 P.M. Explanation:
(P + Q + R)'s 1 hour's work =1+1+1=37.81012120
Work done by P, Q and R in 2 hours =37x 2=37.12060
Remaining work =1 -37=23.6060
(Q + R)'s 1 hour's work =1+1=11.101260
Now,11work is done by Q and R in 1 hour.60
So,23work will be done by Q and R in60x23=23hours 
2 hours.60116011
So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M
(P + Q + R)'s 1 hour's work =
1+1+1=37.81012120Work done by P, Q and R in 2 hours =
37x 2=37.12060Remaining work =
1 -37=23.6060(Q + R)'s 1 hour's work =
1+1=11.101260Now,11work is done by Q and R in 1 hour.60
So,23work will be done by Q and R in
60x23=23hours 2 hours.60116011So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M
300
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
6 Explanation:
B's 10 day's work =1x 10=2.153
Remaining work =1 -2=1.33
Now,1work is done by A in 1 day.18
1work is done by A in18 x1= 6 days.33
B's 10 day's work =
1x 10=2.153Remaining work =
1 -2=1.33Now,1work is done by A in 1 day.18
1work is done by A in18 x1= 6 days.33300
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
40 Explanation:Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
Then, 4x + 6y =1and 3x + 7y =1.810
Solving the two equations, we get: x =11, y =1400400
1 woman's 1 day's work =1.400
10 women's 1 day's work =1x 10=1.40040
Hence, 10 women will complete the work in 40 days.
Then, 4x + 6y =1and 3x + 7y =1.810
Solving the two equations, we get: x =11, y =1400400
1 woman's 1 day's work =1.400 10 women's 1 day's work =1x 10=1.40040Hence, 10 women will complete the work in 40 days.
300
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
60 Explanation:
(A + B)'s 20 day's work =1x 20=2.303
Remaining work =1 -2=1.33
Now,1work is done by A in 20 days.3
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
(A + B)'s 20 day's work =
1x 20=2.303Remaining work =
1 -2=1.33Now,1work is done by A in 20 days.3
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
300
|
5 5/11Explanation:P can complete the work in (12 x 8) hrs. = 96 hrs.Q can complete the work in (8 x 10) hrs. = 80 hrs.
P's1 hour's work =1and Q's 1 hour's work =1.9680
(P + Q)'s 1 hour's work =1+1=11.9680480
So, both P and Q will finish the work in480hrs.11
Number of days of 8 hours each =480x1=60days = 55days.1181111
P's1 hour's work =1and Q's 1 hour's work =1.9680(P + Q)'s 1 hour's work =
1+1=11.9680480So, both P and Q will finish the work in
480hrs.11 Number of days of 8 hours each =480x1=60days = 55days.1181111300
10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
7 Explanation:
1 woman's 1 day's work =170
1 child's 1 day's work =1140
(5 women + 10 children)'s day's work =5+10=1+1=17014014147
5 women and 10 children will complete the work in 7 days.
1 woman's 1 day's work =170
1 child's 1 day's work =1140
(5 women + 10 children)'s day's work =
5+10=1+1=17014014147 5 women and 10 children will complete the work in 7 days.