J. Marion Sims
Henrietta Lacks
Tuskegee
Math
More Math
100
What field of study did Sims develop?
Gynecology
100
What type of cancer did Lack's have?
Cervical Cancer
100
Where did the Tuskegee Study take place?
Alabama
100
Evaluate: (7*9+1)0.5
8
100
Calculate the area of a triangle with sides 3, 4, and 5 m.
6 m2
200
Where did Sims conduct his experiments?
Montgomery, Alabama
200
What is the name given to Lacks's cell line?
The HeLa cell line
200
How many subjects were used in the Tuskegee Study, what were their race and their gender?
600, black, and male
200
If Sally has 12 black rubber bands, 9 blue rubber bands, 24 red rubber bands, and 14 pink rubber band in a bag all mixed up and randomized, how many bands does she have to pull in order to ensure that she has at least one band of each color?
What is 51 rubber bands?
200
What is the probability that, when 2 dice are rolled, their sum is more than 4?
5/6
300
What made Sims's experimentation cruel?
He didn't use anesthesia
300
Which hospital did Lacks go to for treatment?
John Hopkins Hospital in Baltimore
300
How long did the Tuskegee Study go on for?
40 years
300
What is the length of the diagonal that intersects the center of a box with the dimensions 6cm x 8cm x 10cm?
10√2 cm
300
Evaluate: 1 + 2 + 3 + ... + 20
210
400
Does the current medical community see Sims's experiments as ethical?
No
400
Why were Lacks's cells particularly important?
Her cells were the first to be in an immortalized cell line
400
How many many black men in the Tuskegee Study had contracted syphilis?
399 black men
400
Name this person:
Martin Luther King Jr.
400
How many factors does 5,000,000 have?
56
500
When did Sims's experimentation occur?
1845-1849
500
What is one of the applications of Lacks's cells in the medicine?
Researching AIDS, Curing Polio, Mapping Genes
500
What was the cure for syphilis that was found but never treated?
Penicillin
500
Consider the integer
N = 9 + 99 + 999 + ... + 99...9
Where the last number has 321 digits.
Find the sum of the digits of N.
342
500
Find the sum of all real x such that
(2x - 4)3 + (4x - 2)3 = (4x + 2x - 6)3
7/2