Writing Algebraic Equation
Domain and Range
Slope
Systems Of Inequalites
Polynomials
100
17-x=68
x=51
100
What is the domain of the function?
The domain of a function is the set of possible values for the \(\displaystyle small x\) variable. The range would be the possible values for the solution,
100
What is the slope of a line that runs through points: (-2, 5) and (1, 7
2/3
100
y≤2x-1
y>-2x+3
100
Write polynomial P as a product of linear factors : P(x) = x2 - 4.
P(x) = (x - 2)(x + 2)
200
A number increased by nine is 15
y+9=15
200
Which of the following does NOT belong to the domain of the function
0
200
A line passes through the points (–3, 5) and (2, 3). What is the slope of this line
–2/5
200
When you graph the system:
y > -2x + 1
y≤ x + 3
Which of the following is a solution?
(2,0)
200
Write polynomial P as a product of linear factors : P(x) = 5x3 -2x2 + 5x - 2
P(x) = (x + i)(x - i)(5x - 2)
300
Thirty Two is twice a number increased by eight
32=2a+8
300
What is the domain of the function?
All real numbers except
300
Which of the following lines intersects the y-axis at a thirty degree angle?
y = x√3 + 2
300
What is one point that lies in the solution set of the inequalities
(1,-2)
300
Write polynomial P as a product of linear factors : P(x) = (x + 2)(20x2 + 41x + 20)
P(x) = 20(x + 2)(x + 5/4)(x + 4/5)
400
15\p=3
5
400
What is the range of f(x) = x^{2}\) ?
All real numbers greater than or equal to 0
400
What is the slope between (8,3) and (5,7
-4/3
400
18y-90> 36
y>7
400
Show that 1 and -3 are zros of polynomial P given by: P(x) = x4 + 4x3 + 6x2 + 4x - 15 and then express P as a product of linear factors.
P(1) = 0 , P(-3) = 0
500
Each piece of candy costs 25 cents. The price of h pieces of candy is $2.00
.25h = 2.00
500
If y > 0, which of these values of x is NOT in the domain of this equation?y = x^2 + 7}{x}\)
-1
500
Which of the following equations has as its graph a line with slope 4
4x=y+7
500
x > 2
y <- 4
500
Show that -2, -3 and 2 are zeros of polynomial P : P(x) = x5 + x4 + 26x2 -16x -120 and write polynomial P as a product of linear factors
P(- 2) = 0 , P(-3) = 0 , P(2) = 0
P(x) = (x + 2)(x + 3)(x - 2)(x - 1 + 3î)(x - 1 - 3i)