y varies directly with x, and y=12 when x=3, what is the constant of variation for their relationship? Hint: k=y/x
4
m=-7 and b=2
y=-7x+2
m=12 and (3,4) is the point on the line
y-4=12(x-3)
y-4=2/3(x+3)
y=2/3x+6
(2,-12) (5,-3)
3
What is the value of y when x=10
The equation y=4x models the relationship between x and y for this scenario. Plug in for x and multiply. x=10
40
m=1/2 and b=6
y=1/2x+6
slope=-2/7 and passes through (5,-2)
y+2=-2/7(x-5)
y-6=5(x+4)
y=5x+26
(0,-5) and (2,3)
4
y varies directly with x, and y=21 when x=24. What is the constant of variation for their relationship?
k=21/24
y=7/8x
m=-7/3 and b=-8
y=-7/3x-8
slope(m)=3 and passes through (-4,6)
y-6=3(x+4)
y-3+-2(x+2)
y=-2x-1
(5,1) (0,6)
1
If x and y vary directly and y=31.2 when x=5.2, the constant of variation for their relationship is k=6. What is the value of y, when x=6.
y=6x
36
m=-6 and b=4
y=-6x+4
m=-3 and passes through (2,-12)
y+12=-3(x-2)
y-14=2(x-1)
y=2x+12
(10,5) and (2,15)
-5/4
What is the value of y when x=-4
The equation y=4x models the relationship between x and y for this scenario. Plug in for x and multiply. x= -4
-16
m=0.5 and b=1.25
y=0.5x+1.25
m=8/3 and passes through (9,-4)
y+4=8/3(x-9)
y+1=-3/4(x+8)
y=-3/4x-7
(36,9) and (18,-3)
2/3