Which digit is in the ten-thousandths place in 34976.15820
2
4 x 7 x 5
140
11/18 + 5/18
8/9
1206 div 6
201
1 1/4 days = _________ hours
30
78630.4728 rounded to the ten's place is
78630
17 x 7 - 17 x 3
68
17 x 4
0.15 = _____________ common fraction
3/20
2250div25
90
MMXXIII = ____________ (Arabic Numerals)
2023
5 x 103 + 3 x 100 + 7 x 10-1 + 5 x 10-3 = ___________ decimal
5003.705
Remember 103 = 1000 so the 5 is in the thousands place
100= 1 so the 3 is in the ones place
10-1 =.1 so the 7 is in the tenths place
10-3 = .001 so the 5 is in the thousandths place
The LCM of 12 and 16 is
48
7/16 x 48
21
What is the remainder for 74322 divided by 3
3
Add all digits until you get a single digit. Divide that by 3. That is the remainder.
900 nickels = ___________ dimes
450
The number of whole numbers between 3 and 21 is
17
Subtract the two whole numbers and then subtract 1 from that answer
7 1/2 x 5 1/2
41 1/4
square the fraction (1/4)
add integers (12)
multiply by fraction portion of the original problem (12 x 1/2 = 6)
add that answer to the product of the integers
(7 x 5 + 6)
What is the remainder of
5032 divided by 4
8
Use the remainder you get when you divide ONLY the last 2 digits of the dividend by the divisor.
20 ounces = _____________ cups
2.5 cups
If 56 stars cost 35 cents then 24 stars cost ____
15 cents
Each set of 8 cost 5 cents (56 is 7 sets of 8, 7 sets x 5 cents for each set = 35 cents)24 has 3 sets of 8 and each set is 5 cents so that is 15 cents
3/5 = ___________%
60%
What is the remainder?
4962 divided by 9
3
add digits until you have a single digit, that is the remainder unless it is 9. if 9, remainder is 0
65 days = __________ weeks
9 2/7 weeks
The sum of the two largest primes less than 25
42
23 and 19 are the two largest prime numbers less than 25
36 4/11% = ______________ common fraction
4/11
what is the remainder
5463 divided by 11
9 (check my work please, in case I am wrong)
Start with the ones digit and add every other digit to the left (3 + 4 = 7),( 6 + 5 = 11)
If the first sum (7) is less than the second sum (11) add 11 to the first sum (7 + 11 = 18)
Subtract the second sum from the first sum 18-11 = 9