Packet 1
Packet 2
Packet 3
Packet 4
Packet 5
100

Packet #1 Questions #3

Yes

100

Packet #2 question 11

If a LINE is PERPENDICULAR to the RADIUS then it is TANGENT  to the CIRCLE
100

Packet #3 question 1

x = 9

100

Packet #4 Question 3

x = 13 so JL = 35

24/4x-12 = 21/2x+9

100

Packet #5 Question 5

n = 9

interior = 140 so exterior = 40

360/40 = number of sides

200

Packet 1 Questions #14

x = 11

y = 5

200

Packet #2 Questions 15

they win the game

200

Packet #3 Question 4

               2,11,12 and 20,6,15

8+8<17  NO

2 + 11 > 12  YES

6 + 15> 20 YES

15+19 = 34 NO


200

Packet #4 Questions 7

Yes by SAS

8/12 = 10/15 and there are vertical angles

200

Packet #5 question 8

x = 8

there are 8 sides so 360/8 = 45 exterior angle

180 - 45 = 135 interior angle

21x - 33 = 135

300

Packet #1 Questions #8

x = 8 but 

angle = 153

300

Packet #2 Question 18

invalid - 

valid would have been "if a number is a whole number then it is a rational number"

300

Packet #3 Question 9

RT, ST, RS

Smallest side is across from smallest angle

300

Packet #4 question 21

x =  8sqrt3

y = 8

300

Packet #5 Question 11

x = 7 so TR = 13

diagonals are congruent

400

Packet #1 Question #4

Endpoint is (-5,3)
400

Packet #2 questions 20

Law of detachment

400

Packet #3 Question 14

AAS   HJG = IKH

this should have a triangle sign in front and the symbol should be a congruence symbol

400

Packet 4 Question 27

17.5   Sin 39 = 11/x  this is a division problem

400
Packet #5 question 14
x = 8


diagonals bisect the angles of the rhombus

500

Packet #1 Question #22

y = 1/2 x - 4   and y = -2x + 1 

slopes are negative reciprocals for lines are PERPENDICULAR

500

Packet #2 Question # 27

False 

All the pep band members are in marching band but none of them are also in chorus

500

Packet #3 Question 20 Reason #2

Alternate Interior Angles are congruent

500

Packet #4 Question 28

55.8

Tan x = 28/19  this is an INVERSE question

500

Packet #5 question 21

(-4,3)

since the diagonals bisect each other (2,5) is a midpoint

(x + 8)/2 = 2 and (y +7)/2 = 5