5th Grade Volume
5th Grade Measurement Conversions
5th Grade Orders of Operations
Multiple Choice - Random
100

 How much salt is needed to fill a pit that is 10m tall and 8m wide and 12 m long?

960 cubic meters

100

73 m = ____ mm

73,000 mm

100

(20 + 12) ÷ 4

8

100

Select the length that is equivalent to 0.05 kilometer. Mark all that apply.

A) 50 meters
B) 5,000 centimeters
C) 0.5 hectometer
D) 50 decimeters

A and B

200

The length, width, and height of a rectangular prism are 5 cm, 3 cm, and 2 cm, respectively. What is the volume of the prism?

30 cubic cm

200

22 m = ____ cm

22 m = 2,200 cm

200

(37 − 17) × (240 ÷ 20) − 22 × 4

152

200

180 inches = ? feet

A) 15 ft
B) 12 ft
C) 6 ft
D) 5 ft

A

300

What is the volume? 


L= 4  W=3  H=8 

96 cubic units 

300

Each parking spot is 8 feet wide. A parking lot has 24 parking spots side by side. What is the width (measured in yards) of the parking lot?

8 x 24 = 192 

192 feet = 64 yards 

The width of the parking lot is 64 yards.

300

50 + 6 × 11 − 4

112

400

What could be the possible dimension of a box with a total volume of 108 cubic units?

(Must include L, W, H) 

Answers may vary

(12, 3, 3) (6, 9, 2) etc 

400

Each roll of tape is 30.5 feet long. A box contains 454 rolls of tape. In total, there are about ___________ yards of tape.

 a. 500 

b. 5,000 

c. 15,000

30.5 x 454 = 13,847 feet 

13,847 feet = 4,615.66 yards 

Answer is (b).

400

9 × (12 − 8) + 28 ÷ 7

40

500

Prism A: L= 9 cm W= 5 cm H= 8 cm 

Prism B: Base= 72 cm H= 6 cm 

What is the total volume of prism A and prism B combined?

792 cubic cm 

500

9 inches of ribbons are needed for wrapping each present. How many presents can be wrapped with 6 yards of ribbons?

6 yards = 216 inches 

216 ÷ 9 = 24 

24 presents can be wrapped with 6 yards of ribbons.

500

18 − (21 − 5) ÷ (22 − 18)

14