Equations and Inequalities
Unit Rate
Percents and Ratio
Geometry
Definitions
100

−6k − 13 = 83

k=-16

100

Amy drove to her mother’s house, which is 204 miles away. If it took her 3 hours, what was her average speed?

68 miles per hour

100

A roll of 40 quarters weighs 8 ounces. Which proportion can be used to find the weight in ounces, w, of 200 quarters? 

A. 40/8 = 200/w 

B. 40/w = 8/200 

C. 40/200 =  w/8 

D. 40/8+w = w/200

100

Find the volume

168 m3 

100

reciprocal

The inverse of a fraction

200

8x = -10x + 36

x = 2

200

Which is the best buy? 6 shirts for $25.50, 4 shirts for $18.00, or 5 shirts for $21

$21.00 / 5 shirts = $4.20 per shirt- this is the best buy

200

Bed, Bath and Beyond has a 20% off coupon. If I buy a towel normally priced $60, how much would I pay after using the coupon?

$48

200

find the circumference 

200.96 in

200

hypotenuse

The longest side of a right triangle. The side opposite the right angle

300

5(2x + 3) = 3(4x + 3) - 2(3x + 2)

x = -4

300

Jacky needs to ride her bike to her friend’s house 96 miles away. She is riding at an average rate of 15 miles per hour. She has 6 hours to get there. Will she make it?

No

300

In an election, 350 people voted for Class President. Asuman got 58% of the votes. How many votes did Asuman get?

203 votes

300

find the area of number 8

834.55  mm2

300

supplementary angles

two angles that add up to 180 degrees

400

7/10n+ 3/2 = 3/5n +2 

n=5

400

Five lemons cost $1.80. What is the cost per lemon?

$0.36

400

If you start with $100, spend $32, but then return an item and get $7 back, what percent of your money do you still have?

75%

400


find the surface area 

202 m

400

complimentary angles

angles that add up to 90 degrees

500

12 + 5x - 8 = 12x - 10

x=2

500

Five lemons cost $1.80. At this rate, what is the cost of 9 lemons?

$3.24

500

A crew is made up of 8 men; the rest are women. 66% of the crew are men. How many people are in the crew?

12 people 

500

 What is the length of DE

2.25

500

adjacent

having a common boundary or edge