Work-Energy Theorem
Forces and Potential Energy
Conservation of Energy/power
100

This is the equation for the work-energy theorem, stating that the net work done on an object equals its change in this quantity.

What is work equals the change in kinetic energy?

100

This fundamental force is responsible for elastic potential energy in a spring, and its magnitude is given by Hooke’s Law.

What is the spring force?

100

This fundamental principle states that energy cannot be created or destroyed, only transformed from one form to another.

What is the Law of Conservation of Energy?

200

If a 5 kg object speeds up from 2 m/s to 6 m/s, the net work done on it is equal to this value (in joules).

What is 80 J?

200

The negative derivative of gravitational potential energy (U=mgy) with respect to height gives this quantity.

What is the gravitational force (Fg=−mg)?

200

If a 2 kg object is dropped from 10 meters, its speed just before hitting the ground (ignoring air resistance) is this value in m/s.

What is 14 m/s?

300

A 10 N friction force acts over 4 m on a sliding object. If the object’s KE decreases by 50 J, the work done by other forces (if any) must be this value.

What is –10 J?

300

If the potential energy of a system is given by U(x)=4x^2−2x, the force acting on the particle at x=1 m is this value (in newtons).

What is –6 N?

300

A motor delivers 500 watts of power while lifting a 50 kg crate at constant speed. The crate is being lifted at this speed in m/s.

What is 1.02 m/s?

400

A spring (k=200 N/m) is compressed by 0.1 m and launches a 0.5 kg block. If no other forces act, the block’s final speed is this value (in m/s).

What is 2 m/s?

400

A particle's potential energy is given by U(x)=x^3−6x^2+9x The position(s) of stable equilibrium (where force is zero and potential energy is minimized) occur at x= this value.

What is x=3?

400

A spring (k=400 N/m) is compressed 0.2 m and launches a 0.5 kg block horizontally. If 10% of the energy is lost to friction, the block's speed is this value in m/s.

What is 5.37 m/s?

500

A 2 kg object moves along the x-axis with a variable force F(x)=3x^2 acting on it. The work done by this force from x=1 m to x=3 m, and thus the change in KE, is this value (in joules).

What is 26 J?

500

A block slides frictionlessly on a vertical circular track of radius R. If released from rest at the top, the magnitude of the normal force at θ=60∘ from the top is this multiple of its weight (mg).

What is 2.5?

500

A pendulum of length 2 m and mass 1 kg is released from 60° to the vertical. The tension in the string when it passes through the lowest point is this value in newtons.

What is 19.6 N?