f(x) > 0
f(x) < 0
f(x) = 0
End Behavior
IVT
100

Given the function sign chart, state where f(x) > 0.

f(x) > 0 on the interval (-5, 0) U (0, 1)

100

Given the function sign chart, state where f(x) < 0.

f(x) < 0 on the interval 

(-oo, -3)U(1,7)

100

Given the function sign chart, state where f(x) = 0.

f(x) = 0 at x = -6, x = 0, x = 1, and x = 7

100

State the end behavior of the function below:

f(x)=5.3x^4+7x+1

x->-oo, f(x)->+oo

x->+oo,f(x)->+oo

100

What does IVT stand for?

Intermediate Value Theorem 
200

State where f(x) > 0

f(x)=-x^2(x-3)(x+1)

f(x) > 0 on the interval (-1, 0)U(0,3)

200

State where f(x) < 0.

f(x)=(x+3)(x-4)(x+1)^2

f(x) < 0 on the interval (-3, -1) U (-1, 4)

200

State where f(x) = 0

f(x)=-2x(x-3)(x+4)

f(x) = 0 at x = 0, x = 3, and x = -4
200

State the end behavior of the function below:

g(x)=-1/2x^2+5

x->-oo,g(x)->-oo 

x->+oo,g(x)->-oo

200

The function must have at least one zero on the interval(s): 

(-2, -1); zeros at x = 3 and x = 5.

300

State where the function is positive.

f(x)=-2(x-4)(x+2)


The function is positive on the interval (-2,4).

300

State where the function is negative.

f(x)=(3-x)(x+1)(x-1)

The function is negative on the interval 

(-1,1)U(3,+oo)

300

State the zeros of the function. Include multiplicity.

f(x)=x(3-x)(5-x)^2

The zeros of the function are at x = 0, x = 3, and x = 5 (multiplicity of 2).
300

State the end behavior of the function

f(x)=-x^2(3-x)(x+5)^2

x->-oo, f(x)->-oo

x->+oo,f(x)->+oo

300

The function must have at least one zero on the interval(s):

(1, 2), (3, 4), (6, 7). Zeros at x = -1

400

State where the value of f(x) is positive.

f(x)=x^3+4x^2-x-4

f(x) is positive on the interval 

(-4,-1)U(1,+oo)

400

State where the value of f(x) is negative.

f(x)=x^5+5x^4+6x^3

f(x) is negative on the interval 

(-oo,-3)U(-2,0)

400

State the x-intercepts of the function.

f(x)=x^3+3x^2+4x+12

The x-intercepts of the function are at x = -3
400

State the end behavior of the function.

g(x)=-x(x+1)^2(5+x)^2

x->-oo, g(x)->+oo

x->+oo,g(x)->-oo

400

Given the table, f(x) has to have at least how many zeros?


At least 4 zeros
500

State where f(x) > 0.

f(x)=-x^4-x^3+12x^2

f(x) > 0 on the interval (-4, 0) U (0, 3)

500

State where f(x) < 0.

f(x)=-x^3+x^2+4x-4

f(x) < 0 on the interval 

(-2,1)U(2,oo)

500

State the roots of the function.

f(x)=x^4-64x

The roots of the function are at x = 0 and x = 4

500

State the end behavior of the function

f(x)=(2x-5)(x-2)(x^2+1)(4-x)^2

x->-oo,f(x)->+oo

x->+oo,f(x)->+oo

500

The function must have at least one zero on the interval(s): 

(0, 1) and (3, 4). Zeros at x = -2