Projectile Motion
Circular Motion
Work and Energy
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100

Identify a place/item where projectile motion is observed.

Ball rolling off desk

Parachute released from plane

etc

100

The period is the ________________

Time taken for an object/body to complete one revolution.

100

What is the SI unit for energy?

Joules

100

The letter (s) represents


displacement

100

The letter (g) represents

Gravitational force

200

A ball is free falling from a height of 40m. Take the acceleration due to gravity.

Calculate the velocity of the ball at the point of impact.

v = u + at

v = 0 + 9.8 x 2.9s

v = 28 m/s downwards

200

Complete the missing words;

Projectile motion occurs when an object travels in a C___________ path.

The speed remains CO__________

The velocity CH__________


Circular path

Constant

Changes

200

Calculate the torque

A bus driver applies a force of 45N on a steering wheel.

The radius of the wheel is 30cm. If the force is applied at 90° calculate the force on the steering wheel.

ꚍ = r ꓕ F

ꚍ = 0.3 x 45

  = 13.5 N m clockwise.

200

Projectiles launched horizontally the velocity remains CONSTANT to its horizontal velocity.

TRUE/FALSE

True

200

A bus driver applies a force of 145N on a steering wheel.

The radius of the wheel is 40cm. If the force is applied at 90° calculate the torque on the steering wheel.

ꚍ = r ꓕ F

ꚍ = 0.4 x 145

  = 58 N m clockwise.

300

A ball is hit horizontally from the top of a 40m high cliff with a velocity of 25 m/s to the right. Using an acceleration due to gravity and ignoring air resistance, calculate the following values.

The time it takes for the ball to land

s= ut + ½ at2

40= 0 + ½ 9.8t2

t = √40/4.9

t =2.86 s


300

Give the formula for Centripetal acceleration.

ac = v2/r

300

A toy car has a mass of 150g is released from a height of 1m. The car rolls down the track and travels inside the loop.

Calculate the potential energy.


PE = mgh

PE = 0.150 x 9.8 x 1

PE = 1.47 Joules

 

300

An athlete is swinging a ball of mass 7kg in a circular path. The ball is moving at 20m/s in a circle with a radius of 1.6m.

Calculate tensile (tension) in the wire.

Given the acceleration is 250 m/s/s

F = ma

F = ma

F = 7kg x 250m/s/s

F = 1.8 x 10^3 N

300

A wind turbine has blades 55m that rotate at a frequency of

20 revolutions per minute.

Calculate the frequency.

Frequency = rev/sec

                    = 20/60

                    = 0.33Hz

400

Fill in the missing words.

•Gravity is a D________ force so there is no force in the H__________ DIRECTION.

•The projectiles velocity D________ as it RISES.

•The projectile has UNIFORM velocity in the H__________ DIRECTION.

Downward force

Horizontal

Decreases

Horizontal

400

A wind turbine has blades 55m that rotate at a frequency of 20 revolutions per minute.

First calculate the period then the speed for the blade tips.

Period = 1/f

v = 2πr/T


Frequency = 0.33Hz

Period = 1/f

            = 1/0.33

            = 3 seconds

v = 2πr/T

v = 2x π x 55/ 3

   = 115.2 m/s

400

Complete the sentence.

Torque occurs when there is a P_____point and a F_______ applied some DI_______ from the PIVOT point.

Pivot

Force

Distance

400

FN = Fnet   - Fg

Fnet =  14.7N

Fg   = - 1.47N (downward force)

FN   = ?

Calculate FN

FN = 14.7   - (-1.47)

FN = 14.7+ 1.47

     = 16.2N

400

An athlete is swinging a ball of mass 7kg in a circular path. The ball is moving at 20m/s in a circle with a radius of 1.6m.

a) Calculate the magnitude of the acceleration.

ac = v2 / r

ac = v2 / r

ac = 202 / 1.6

ac = 250 m/s/s

500

An athlete in a long jump leaps with a velocity of 7.5 m/s at an angle of 30 degrees to the horizontal.

What is the maximum height gained by the athlete given the maximum velocity is 6.5 m/s.

v2 = u2 + 2as

v2 = u2 + 2as

0 = 3.752 + 2 x 9.8 x s

s =3.752  / 2 x (9.8)

s = 71.7 cm

500

A wind turbine has 55m length blades which travel a distance of 150m in 2s.

First calculate the angle.

Ꝋ = distance/length

What angular velocity does the turbine rotate?

Ꙍ= ∆Ꝋ /t

Ꙍ= ∆Ꝋ /t

Ꝋ = distance/length

    = 150/55

    = 2.72 rad

    = 2.72 x 180/π

    = 156.3°

500

A mass 1500kg is released from a height of 1m. The mass rolls down the track.

E = 14 700 Joules

Calculate the speed as it reaches the bottom.

E = 1/2 mv2

E = ½ mv2

14700 = ½ 1500v2

14700 = 750v2

v = √14700/750                v = 4.43 m/s

500

A wind turbine has 60m length blades which travel a distance of 100m in 2s.

First calculate the angle.

What angular velocity does the turbine rotate?


Ꙍ= ∆Ꝋ /t

Ꝋ = distance/length

Ꙍ= ∆Ꝋ /t

Ꝋ = distance/length

    = 100/60

    = 1.67 rad

    = 1.67 x 180/π     = 95°

500

Fill in the missing words.


•A conical pendulum is a mass that travels in a horizontal direction on a ST________.

•A banked track is one where the track is inclined at some angle to the H____________.

•Banking tracks eliminate the need for FR__________ FORCE to turn.

•The speed at turns in banking tracks is known as D________ SPEED. 

String

Horizontal

Frictional

Design