What is one way you can graph an equation in Slope-Intercept Form?
Plot the y-intercept and then count slope if Slope-Intercept Form
Make a table of values and plot the points
y = 9x - 8
Slope-Intercept
Write the equation in Slope-Intercept Form for a line with a slope of 6/7 and a y-intercept of -8.
y = 6/7x - 8
How do you graph an equation in Standard Form?
Find the x- and y-intercept and plot
In the following linear equation, what is the y-intercept? y = -3/4x + 4
3x - 2y = -14
Standard Form
Write an equation for a line in Slope-Intercept Form whose y-intercept is 4 and goes through the points (5, 5) and (10, 6)
y=1/5x +4
Identify the slope of the following equation:
y - 5 = -6 (x + 9)
-6
What is the Standard Form of a Line?
Ax + By = C
y - 5 = 2/3(x - 7)
Point-Slope Form
Convert this to Standard Form:
y = -4x + 10
4x + y = 10
Graph the following equation. Include two points. 2x + y = 10
Graph should begin with a point on the y-axis at 10 and x-axis at 5.
What is Point-Slope Form of a Line?
y - y1 = m (x - x1)
Graph the following equation. 8x + 4y = 16
Should be rewritten as y = -2x + 4 and then graphed.
Write the equation of the line that passes through the points (0, 5) and (4, 17) in Point-Slope Form.
y -17 = 3(x - 4)
y - 5 = 3(x -0)
Rewrite the following equation in Standard Form:
y = 8x - 15
-8x + y = -15
Is x = 2 a solution to the equation 2(x - 5) + 3 = 13 ?
No it is not a solution.
y=1/2x - 3
x + 2y = 6