(5p2-3)+(2p2-3p3)
7p2-3p3-3
(5x3)(2x2)
10x5
-|15|
-15
|x+4|>2
x>-2 x<-6
If I have an absolute value of negative 10, how would I write it and what is it's solution?
|-10|=10
(4+2n3)+(5n3+2)
7n3+6
5x2(5x2+2)
25x4+10x2
|x-4|=2
x=6,2
|b-8|+10>22
b>20 b<-4
What do I do with my exponents when I add/subtract polynomials?
Keep and combine like terms
(5a+4)-(5a+3)
1
(x+2)(x-2)
x2-4
-5|x-2|=-45
x=11,-7
4|5x-2|+7>39
x>2 x<-3/2
What do I do with my exponents when I multiply? Divide?
Add/Subtract
(a3-2a2)-(3a2-4a3)
a2-3a3
3b3(3b3+1)
9x6+3b3
-2|n+2|+3=-21
x=10,-14
-5|-n+7|>-50
n>-3 n<17
What are my steps for solving absolute value equations?
Isolate absolute value, check c, provide 2 equations, solve and plug in.
(3-6n5-8n4)-(-6n4-3n-8n5)
2n5-2n4+3n+3
(5x2+4x-2)(2x2+3x)
10x4+23x3+8x2-6x
|2b-9|=|b-6|
b=3,5
12a+6/6>2
a>.5 a<1.5
What are my steps for solving absolute value inequalities?
Isolate, check c, set up 2 equations, flip my negative >< signs, find the 2 inequalities.