Square Root Function
Graph y = √(x+1) and state the domain and range.
Graph on Desmos to check!
Domain: { x | x >= -1}
Range: { y | y >= 0}
\sqrt{180}
6\sqrt{5}
\sqrt{12}-\sqrt{3}
\sqrt{3}
Graph y = 2√(x-2) + 2 and state the domain and range.
Graph on Desmos to check!
Domain : { x | x >= 2}
Range: {y | y >= 2 }
3\sqrt{288a^2b}
36a\sqrt{2b}
2√(3) * 3√(12)
36
Compare y = 1/2√(x+1) to the parent graph y = √(x).
It is less steep and shifted to the left 1.
√(20ab^3)
2b √(5ab)
\sqrt{5}(\sqrt{2}+4\sqrt{2})
5\sqrt{10}
Compare y = 2√(x) -3 to the parent graph y = √(x).
It is more steep and shifted down 3.
\frac{3}{\sqrt{18}}
\frac{\sqrt{2}}{2}
(4-√(5))^2
21-8√(5)
Compare y = -2√(x + 2) -4 to the parent graph y = √(x).
It is upside down, more steep, left 2 and down 4.
5/(√(7) + 6)
(5√(7) -30)/(-29)
2√(1/2) + 2√(2) -√(8)
√(2)