Quadratic Formula + Word Problems
Systems + Word Problems
Solve by Graphing
Solve by Factoring + Word Problems
Square Roots
100

Find the Discriminant to determine the number of solutions

2x2-2x-4=0

36, 2 real solutions

100

Rewrite each equation as a system of equations and then use a graph to solve. 

x2-6x=2x-16

(4, -8)

100
Solve the following by graphing: 


x2+4x+3

x = -3

x = -1

100
Solve by factoring: 

x2-2x-15=0

x= -3

x= 5

100

Simplify: 

4Sqrt(84x5)

8x2Sqrt(21x)

200

Solve using the quadratic Formula: 

2x2-2x-4=0

x = -1

x = 2

200

Find the solution of the system of equations: 

y=-4x2+x+1

y=-7x+1

(0,1) and (2, -13)

200

Solve by graphing: 

0=x2+6x+9

x = -3

200

Solve by factoring: 

x2+10x+25 = 0

x = -5

200

Simplify: 

Sqrt(35x) Sqrt(21x)

7x Sqrt(15)

300

Solve using the quadratic Formula: 

x2-6x=-7

x = 4.41

x = 1.59

300

Find the solution to the system of equations: 

y = x2+6x+9

y = 3x

No solution

300

Solve by graphing: 

-4x2=3

No real solutions

300

Solve by factoring: 

2x- 2x - 4=0

x = -1

x = 2

300

Solve using Square Root Method: 

x2=-100

No real solutions

400

If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 ft per second, then its height h after t seconds is given by the equation h(t) = -16t2+128t. What is the max height, and how long will it take the rocket to reach the max height?

Max Height: 256 ft. 

Time to reach Max Height: 4 seconds

400

Since opening day, attendance at Pool A has increased steadily while attendance at Pool B first rose then fell. Equations modeling the daily attendance (y) and number of days since opening day (x) are shown:

Pool A: y=28x+4

Pool B: y=-x2+39x+64

On what day was the attendance the same at both pools?

Day 15

400
Solve by graphing: 

x2+5=6x

x = 1

x = 5

400

Solve by factoring: 

3x2-6x=24

x = -2

x = 4

400

Solve using Square Root Method

5x2+10=330

x = +/- 8

500

If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 ft per second, then its height h after t seconds is given by the equation h(t) = -16t2+128t. After how many seconds will the rocket be 112 feet above the ground?

t = 1 second and t = 7 seconds

500

The equations below model the numbers of two portable music players sold (y) and days after both players were introduced (x).  

Music Player A:  y = 191x – 32  

Music Player B:  y = ‐x2 + 200x + 20

On what day(s) did the company sell the same number of each player? And how many were sold?

Day 13

2451 Sold

500

Solve by graphing: 

-4x2=64 - 32x

x = 4

500

A picture inside a frame has an area of 375 cm2. What is the width, x, of the frame if the length is 30 cm. by 20 cm. 

2.5 cm. 

500

Solve using Square Root method: 

2(x-8)2-5 = 283

x = 20

x = -4