S = 2B + ph
Solve for h.
h = S - 2b
p
|x| = 4
x = 4 & -4
3p−1=5(p−1)−2(7−2p)
p = 3
-8(6 +x)<16
x > -8
Simplify. State your answer in standard form.
(-a3+4a-3)+(5a3-a)
4a3+3a-3
K = 1/2mv2
Solve for m.
m = 2K
v2
|x - 6| = 14
x = 20, -8
-5(8n - 4) - n = - 16 - 5n
n = 1
Jim has earned scores of 73, 85, 91, and 82 on the first four of five math tests for the first marking period. He would like to finish the marking period with a test average of at least 82. What is the minimum score he needs to earn on the 5th math test in order to achieve his goal. Write an inequality to represent your answer.
x is greater than or equal to 79
Simplify. State your answer in standard form.
-3(x3 + 5x2 − 8) + (4x2 + 6x − 1)
-3x3 - 11x2 + 6x + 23
F = mv2
r
Solve for m.
m = Fr
v2
Solve for r:
−2|−2r−4|=−12
r = -5, 1
-15 - 5x = 5(-x - 3)
Infinite Solutions (R)
Solve.
-7 < 4x +1 < 5
-2 < x < 1
Simplify. State your answer in standard form.
(4x2-3x+7) - (2x2+5x-3)
2x2 - 8x + 10
S = 2w2 + 4hw
Solve for h.
h = S -2w2
4w2|3x - 5| = -10
No solution (empty set)
-10 - 5x = 5(-x - 3)
No solution (empty set)
Solve
-3p + 1 < -11 OR p + 4 < 6
p > 4 OR p < 2
Multiply and simplify.
(3x−5)(2x−1)
6x2−13x+5
Rewrite the equation in slope intercept form: y=mx+b.
6x + 1/3y = 2
y = -18x + 6
Solve.
−5|4+n|<−15
n>−1 or n<−7
What value of y would create an equation that has infinitely many solutions?
4(2x + y) = 8x + 12
y = 3
Solve the compound inequality.
9 + 2x > 15 or 7 + 4x < -9
x > 3 or x < -4
Multiply and simplify.
(2x−3)(4x2+6x+9)
8x3−27