Does the equation below open up or down?
y=-4x^2+3x-11
Down
0=x^2-4
x=+-2
4x^2-16=0
x=+-2
Listed below is the quadratic formula for assistance. Give the formula for the discriminant.
(-b+-sqrt(b^2-4ac))/(2a)
b^2-4ac
In real world scenarios, we can model free-falling objects with parabolas and quadratics. Which way will the parabolas open?
Down
The axis of symmetry for the equation below.
y=x^2+4x+3
x=-2
What method of solving the quadratic is this?
x^2-10x+21=0
x^2-10x=-21
x^2-10x+25=-21+25
(x-5)^2=4
x-5=+-2
x=3, 7
Completing the Square
9x^2-64=0
x==+-8/3
If the discriminant is positive, then there are this many solutions.
2
A pitcher throws a ball in the air. The ball is modelled by the equation given below, where x is the time, in seconds, and y is the height, in feet. When is the ball at its peak?
y=-16x^2+96x+6
3 seconds.
The vertex for the equation below.
y=3x^2-6x
(1, -3)
Solve the quadratic.
0=x^2+3x-4
x=-4, 1
2x^2+8x+6=0
x=-3,-1
How many solutions does this equation have?
x^2-8x+16=0
1
A pitcher throws a ball in the air. The ball is modelled by the equation given below, where x is the time, in seconds, and y is the height, in feet. What is the highest point that the ball reaches?
y=-16x^2+96x+6
150 ft
The solutions to the graphed equation can be found on this axis.
x-axis
Solve the quadratic.
x^2+23x-50=0
x=-25,2
11x^2-8x+12=0
No real solution
If the discriminant is 0, there are this many real solutions.
1
A pitcher throws a ball in the air. The ball is modelled by the equation given below, where x is the time, in seconds, and y is the height, in feet. Does the ball fly higher than 100 feet?
y=-16x^2+96x+6
Yes, it does, because the discriminant is positive.
Sketch a graph opening up that would have one solution. Your graph should only be the axes and your graph.
The graph should be all positive except for the vertex, which is on the x-axis.
Solve the quadratic.
x^2+5x-336=0
x=-21,16
3x^2-7x-26=0
x=-2, 13/3
How many solutions does this equation have?
3/4x^2-6x+17/12
2
A pitcher throws a ball in the air. The ball is modelled by the equation given below, where x is the time, in seconds, and y is the height, in feet. How long is the ball in the air? (Round to the nearest tenth of a second)
y=-16x^2+96x+6
6.1 seconds