Factoring
Factor the Polynomial
x^2-9x+8
(x-1)(x-8)
Graph the polynomial:
y=x^2+3
What is the value of the polynomial when x=5? Use Synthetic AND regular substitution to show.
f(x)=x^2-4x-10
f(5)=-5
Factor the polynomial completely
2x^5-2x^3-24x
2x(x-4)(x+3)
Graph
y=3(x-1)(x+2)(x+1)
Simplify:
(\frac{3x^3y^2}{9xy})^2
\frac{x^4y^2}{9}
Factor the polynomial by synthetic substitution: given (x+6) is a factor
y^3+6y^2-3y-18
(x+6)(x^2-3)
Divide the polynomial using synthetic division:
(x^3+2x^2-10)\div(x-4)
(x^2+6x+24+\frac{86}{x-4})