i^38
i^38=i^36cdoti^2=(1)cdot(-1)=-1
"Solve "x^2+9=0
x^2=-9
sqrt(x^2)=pmsqrt(-9)
x=pm3i
(x^2+15x+56)/(x^2+7x)div(x^2-64)/(2x+16)
(x^2+15x+56)/(x^2+7x)cdot(2x+16)/(x^2-64)
((x+7)(x+8))/(x(x+7))cdot(2(x+8))/((x+8)(x-8))
(2(x+8))/(x(x-8))
3/(x+2)=5/x
3/((x+2))cdot((x)(x+2))/1=5/xcdot((x)(x+2))/1
3x=5(x+2)" "implies" "3x=5x+10" "implies" "-2x=10
x=-5
(3+4i)(2-i)
6-3i+8i-4i^2
6+5i-4(-1)
6+5i+4
10+5i
"Solve "3x^2-x+3=0
x=(-bpmsqrt(b^2-4ac))/(2a)" "implies" "x=(1pmsqrt(1-4(3)(3)))/(2(3))
x=(1pmsqrt(-35))/6=(1pmsqrt(35)i)/6
x=1/6pmsqrt(35)/6i
2/(5a)+4/(3b)
2/(5a)cdot((3b))/((3b))+4/(3b)cdot((5a))/((5a))
=(6b)/(15ab)+(20a)/(15ab)=(6b+20a)/(15ab)
1/(2x^2)+3/(10x)=1/x-1/(5x^2)
(1(10x^2))/(2x^2)+(3(10x^2))/(10x)=(1(10x^2))/x-(1(10x^2))/(5x^2)
5+3x=10x-2" "implies" "7x=7
x=1
3/(5-3i)
3/((5-3i))cdot((5+3i))/((5+3i))=(15+9i)/(25-9i^2)=(15+9i)/(25-9(-1))
=(15+9i)/(25+9)=(15+9i)/34
=15/34+9i/34