Inverses
Logarithms
Trigonometry
Polynomials
Imaginary #s
100

Find the inverse of the function:

f(x) = 2x3 + 3

cube root ( (x - 3) / 2)

100

Expand the logarithm:

log(ab)2

2 log(a) + 2 log(b)

100

What is the starting point for the function:

y = 4cosθ

(0,4)

100
Classify the polynomial by degree and number of terms:

2n2 - 2 + 3n

quadratic trinomial

100

Simplify the expression:

(6 + i) (-8 + 3i)

-51 + 10i

200

Rewrite in logarithmic form:

xy = 101

logx101 = y

200

Condense the logarithm:

log3u - 5 log3v

log3(u/v5)

200

What is the midline for the function:

y = 3sinθ-2

y=-2

200

Find the zeros of the polynomial:

f(x) = 2x4 + 2x3 - 12x2

x = {2, 0 (mult, 2), -3}

200

Find the aboslute value of the complex number:

|2 - 4i|

2 sqrt(5)

300

Evaluate the logarithm:

log6(1/216)

-3

300

Condence the logarithm:

20 log6x + 5 log6y

log6(x20y5)

300

What is the period of the function:

y = tan3θ

π/3

300

Divide:

(2x2 + 5x - 42) / (x + 6)

2x - 7

300

Sketch a graph with one real root and two complex roots.

*on graph*

400

Rewrite in exponential form:

log550 = k

5k = 50

400

Expand the logarithm:

log4(xy/z)

log4x + log4y - log4z

400

Describe the phase shift AND vertical shift of the function:

y = 4 sin (θ - π/4) - 1

Phase shift: right π/4

Vartical shift: down 1

400

Divide:

(6a2 + 24a - 36) / (a + 5)

6a - 6 - (6/(a+5))

400

Find the equation of the function that has the roots: 

(2 + 5i) and (2 - 5i)

y = x2 - 4x + 29

500

State if the following functions are inverses:

f(x) = (2/(n+1)) + 1
g(x) = (1/(n+1)) + 2

no

500

Condense the logarithm:

2(log5a + log5b) - log5c

log5((a2b2)/c)

500

What is the starting/center point for the function:

y = 3 cos (θ + π) + 2

(-π, 5)

500

Divide:

(k3 - 17k + 8) / (k - 4)

k2 + 4k - 1 + (4/(k-4))

500

Solve using the quadratic formula:

0 = x2 - 6x + 12

3 +/- i sqrt(3)