Algebra 2 Unit 2 Review

imaginary

100

(1+2i)+(2+3i)

3+5i

200

(4-6i)+(5+3i)

9-3i

300

(6+7i)-(5-6i)

1+13i

400

(5+4i)(5+6i)

1+50i

500

13i/6+5i

65/61 + 78/61i

Square Root

100

x²=√49

x1= -√7 

x2= √7

200

x²=√25

x1=-√5

x2=√5

300

x²=√-625

x1=25i

x2=-25i

400

x²=-√289

x1=-√17i 

x2=√17i

500

√x²=√56

x=+- 2√14

Factoring

100

Factor the expression:

x²+11x+10

(x+10)(x+1)

OR

(x+1)(x+10)

200

Factor the expression: 

x²-x-42

(x+6)(x-7)

or

(x-7)(x+6)

300

Factor the expression: 

9x²-25

(3x-5)(3x+5)

OR

(3x+5)(3x-5)

400

Factor the expression:

4x²+36+25x

(x+4)(4x+9)

OR

(4x+9)(x+4)

500

Factor the expression:

8x²+14x=-15

(2x+5)(4x-3)

OR

(4x-3)(2x+5)

Vertex Form

100

Using the vertex point (9,4) write it into an equation using vertex form.

f(x)= a(x-9)²+4 

OR 

y=a(x-9)²+4

200

Using the vertex point (2,8) and the point (4,0) write the equation in vertex form.

f(x)=-2(x-2)²+8

OR

y=-2(x-2)²+8

300

Using the equation y=x²-4x+5 (standard form) find the vertex. 

Vertex: (2,1)

400

Using the equation in standard form, y=x²-16x+ 70, find the vertex and A value and rewrite it in vertex form.

f(x)=(x-8)²+6

OR

y=(x-8)²+6

500

Using the equation: y=-12x-12-2x² Find the vertex and A value and put it into vertex form.

f(x)=-2(x+3)²+6

OR

y=-2(x+3)²+6

Key Features

100

Identify the Domain of this expression: f(x)=6(x-7)²+8

Domain: (-infinity, infinity) 

200

Identify the Domain and Vertex of this expression: f(x)=-7(x-5)²+9

Vertex: (5,9)

Domain: (-infinity, infinity)

300

Identify the Vertex, Domain, AOS of this expression: 

f(x)=-2(x-2)²+3

Vertex: (2,3)

Domain: (-infinity, infinity)

AOS: x=2

400

Find the vertex, domain, and AOS using this expression: f(x)=-2(x-3)+4

Vertex: (3,4)

Domain: (-infinity, infinity)

AOS: x=3

500

Find the vertex, domain, x intercepts, and AOS using this expression: f(x)=-2(x-6)+8

Vertex: (6,8)

Domain: (-infinity, infinity)

AOS: x=6

X intercepts: x1= (4,0) x2=(8,0)