Transformations
Absolute Value Functions
Absolute Value Inequalities
Inverses of Functions
Characteristics of Functions
100

Describe the transformations of the following function in reference to the parent function.

f(x) = 2/3(x - 3)^3 - 1

vertical shrink by a factor of 2/3, horizontal translation right 3, vertical translation down 1

100

Solve for x.

6 + abs(9 + x) = 22

x = 7, -25

100

Solve for x. Write you answer in interval notation.

abs(x + 5)/2<= 2

[-9, -1]

100

Given f(x), find 

f^-1(x)

f(x) = (10-4x)/5

f^-1(x) = (-5x + 10)/4

100

Is the following function even, odd, or neither.

f(x) = -3x^5 - 7x + 5

neither

200

Create a new function, h(x), that transformations f(x) in the follow ways:

-reflection over the x-axis

-horizontal stretch by a factor of 2

-vertical translation up 3

h(x) = -f(1/2x) + 3

200

Solve for x.

2abs(x - 4) + 3 = -19

no solution

200

Solve for x. Write your answer in interval notation.

-8abs(x - 10) < -112


(-oo, -4), (24, oo)

200

Given f(x), find 

f^-1(x)

f(x) = 1/(x + 3) + 2

f^-1(x) = 1/(x - 2) - 3

200

Describe the end behavior of the following function, using proper notation. Then describe domain and range in interval notation.

x -> oo, f(x) -> -oo

x->-oo, f(x) -> 0

D: (-oo, oo) R: (-oo, 0)

300

Create a new function, h(x), that transforms the function f(x) in the following ways:

-vertical stretch by a factor of 3

-reflection over the y-axis

-horizontal shrink by a factor of 3/4

h(x) = 3f(-4/3x)

300

Graph the following function and determine the vertex:

y = 3abs(2x - 2) - 2

vertex: (1, -2)

300

Solve for x. Write your answer in interval notation:

9 + abs(-3 - p) <= -2

No Solution

300

Determine algebraically if the following two functions are inverses. State how you know.

f(x) = 4/(x - 2) - 3

h(x) = 4/(x + 3) + 2

Yes because 

f(f^-1(x)) = x or f^-1(f(x)) = x

300

Describe the end behavior of the following graph using proper notation. Then, describe the domain and range in interval notation.

No end behavior on the right

x->-oo, f(x) -> oo

D: (-oo, 1] R: [0, oo)

400

Describe the transformations of the function below, f(x), in reference to the parent function, p(x)

p(x) = sqrtx, f(x) = -sqrt(3x + 6)

-reflection over the x-axis

-horizontal shrink by a factor of 1/3

-horizontal translation left 2

400

Solve for x.

4abs(7x + 1) + 5 = 9

x = 0, -2/7

400

Solve for x. Write your answer in interval notation.

abs(8 - 3x) - 2 >= -6

(-oo, oo)

400

Consider the following function below. Determine if the inverse is also a function and state how you know.

{(2, 1), (6, -3), (-2, 0), (3, -3)}

No, the inverse is not a function because the function is one-to-many with (6, -3) (3, -3)

400

Describe where the function is increasing and decreasing, then where the function is positive and negative. Use interval notation:

Increasing: 

(-oo, 2)

Decreasing:

(2, oo)

Positive: 

(0, 4)

Negative: 

(-oo, 0), (4, oo)

500

Describe the transformations of the functions:

f(x) = 5/4f(-2x + 3) - 5

-vertical stretch by a factor of 5/4

-reflection over the y-axis

-horizontal shrink by a factor of 1/2

-horizontal translation right 3/2

-vertical translation down 5

500

Write the following function as a piecewise function:

f(x) = -2abs(x - 5) + 3

y = -2x + 13; x > 5 

y = 2x - 7, x <=5

500

Solve for x. Write your answer in interval notation:

6 - 5abs(7 + 5x)>=-109

[-6, 16/5]

500

How would you restrict the domain of the following function to ensure that the inverse is also a function? Write your answer in interval notation.


y = 2x^2 - 12x + 5

[3, oo) or (-oo, 3]

500

Sketch a graph with the following characteristics:

-only negative over the interval (-inf, -2)

only positive over the interval (-2, 1), (1, inf)

-increasing (-inf, -1), (1, inf)