Unit 4: Lines
Determine the slope of the line through the points (12, -18) and (11, 12)
-30
Would the following inequality have an open or closed dot and will it get shaded to the left or right?
-2 < x + 10
open dot, shade right
x > -12
Solve by using substitution.
y = 4x - 9
y = x - 3
(2, -1)
(2x^3yz^2)(-4xy^5z^2)
-8x^4y^6z^4
Simplify
(3x^2 -2x +4) - (x^2 - 8x + 10)
2x^2 + 6x - 6
Write an equation in slope-intercept form of the line that passes through the given point with the given slope.
(4, -2), m=1/2
y = 1/2x - 4
Solve the inequality.
-13y < 26
y > -2
Solve using substitution.
4x + 2y = 10
x - y = 13
(6, -7)
(a^2b^4)(ab)^4
a^6b^8
Simplify (x+7)^2
x^2 + 14x + 49
Write an equation in slope-intercept form of the line that passes through the given point with the given slope.
(4,0); m=undefined
x=4
2x-4>2 and 5x+3<53
3 < x < 10
Solve using elimination.
8x - 6y = -20
-16x + 7y = 30
(-1, 2)
(x^-2 y^4 z^-6)^0
1
Factor 81x^2 - 4y^2
(9x-2y)(9x+2y)
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the given equation.
(-1, 2) 3x - y = 6
y = 3x + 5
Solve the absolute value inequality.
|6x-1|>3
x>2/3 or x<-1/3
Solve using elimination.
2 x + 8 y = 6
−5 x − 20 y = −15
Infinite Solutions
(-10x^-2) / (5x^12)
-2 / x^14
Factor
x^2 - 16x + 63
(x-9)(x-7)
Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the given equation.
(6, 9) -3x + y = 1
y = -1/3x + 11
Solve the following absolute value inequality.
|8x + 2| < -3
No Solution
Solve using either substitution or elimination.
x − 2y = 7
−3x + 6y = −1
No Solution
(4 x^-3 y^9 z^4) / (16 x^-7 y^-1 z^4)
x^4 y^10 / 4
Factor
7x^2 - 31x - 20
(7x+4)(x-5)