Algebra Lesson 9.2 Review

Find the GCF

100

GCF(14, 49)

GCF(14, 49) = 7

200

GCF(45, 75)

GCF(45, 75) = 15

300

GCF(90x²y², 120xy²)

GCF(90x²y², 120xy²) = 30xy²

400

GCF(35m², 95n)

GCF(35m², 95n) = 5

500

GCF(36a²b², 96bc²)

GCF(36a²b², 96bc²) = 12b

Factor using the Distributive Property

100

3a + 9

3(a + 3)

200

2k³ + 10k²

2k²(k + 5)

300

16m² + 24mn

8m(2m + 3n)

400

8p²q - 32pq² + 16p³q³

8pq(p - 4q + 2p²q²)

500

3xz² + 9xy - 18x²yz

3x(z² + 3y - 6xyz)

Factor by Grouping

100

12a³ - 9a² + 4a - 3

(4a - 3)(3a² + 1)

200

21xy - 18by + 14xb - 12b²

(7x - 6b)(3y + 2b)

300

21jk + 15j + 35mk + 25m

(7k + 5)(3j + 5m)

400

4xy - 24y + 6 - x

(x - 6)(4y - 1)

500

12bc - 4bd - 15xc + 5xd

(3c - d)(4b - 5x)

Zero Product Property

100

(x + 7)(x - 8) = 0

x = -7, 8

200

a(a + 8) = 0

a = 0, -8

300

(3x + 1)(x + 4) = 0

x = -¹/₃, -4

400

(m - 2)(5m + 7) = 0

m = 2, -⁷/₅

500

n² + 3n = 0

n = 0, -3