Polar Coordinates
Polar Conic Equations
Converting Coordinates
Converting Equations
Polar to Rectangular
Converting Equations Rectangular to Polar
100

What quadrant is the point (4, -2pi/3) located in?


3rd

100

What is the eccentricity of an ellipse?

any number between 0 and 1

100

Convert the polar coordinates (3, pi/2) to rectangular.

(0, 3)

100

rcostheta=16

x=16

100

x^2+y^2=36

r=6

200

What quadrant is the point (-4, -5pi/6) located in: 

1st quadrant

200

What is the rectangular equation of the directrix for the polar conic r = 6/(1 - 3cos(theta))


x = -2

200

(3, -pi/6)

Convert from polar to rectangular. Exact coordinates please. 


(3sqrt(3)/2, -1.5)

200

r=6

x^2+y^2=36

200

y=10

r=10/sintheta or r=10csctheta

300

Give another set of coordinates for the point 

(4, -3pi/4).  The angle must be coterminal and positive.

(4, 5pi/4)

300

What is the eccentricity and type of conic for the equation

r = 4 / (5 - 3sin(theta))

3/5, ellipse

300

Convert from rectangular to polar: (-2,7)

Theta must be positive, round to 2 decimal places.  Exact radius please.

300

theta=3pi/4

y=-x

300

3x+2y=4

r=4/(3costheta+2sintheta

400

Give two coterminal angles (one positive and one negative) that are pi radians away from 5pi/6. 

-pi/6 and 11pi/6

400

What is the polar equation for the parabola with vertex at (4, pi/2)?


r = 8/(1 + sin(theta))

400

Convert the rectangular point (0, 3) to polar coordinates. 

Answer in radians!

400

r=2sectheta

x=2

400

(x-2)^2+y^2=4


r=4costheta

500

Where is the point (-2, pi/2) located on the polar coordinate plane?  Be specific

2 units directly below the pole.

500

What are the coordinates of the vertices for the polar conic r = 5/(1- 3sin(theta))


(-5/2, pi/2) and (5/4, 3pi/2)

500

Describe the points that have the same coordinates in both the rectangular coordinates and polar coordinates.

Points on the positive x axis.

500

r = 2 / (1 - sin(theta)) 

Write in standard rectangular form

x=4(y + 1)

500

y = x2

r = sin(theta) / cos(theta)  or

r = tan(theta)/cos(theta)  or

r = tan(theta)sec(theta)