Derivatives
Limits
Integrals and antiderivatives

Cross-section
Theorems
100

What is the derivative of 8x^9

72x^8

100

What rule is used when 0/0 is obtained when solving for the limit of a function

L\'Hôpital's rule

100

Antiderivative of x^9

x^10/10

100

Cross-section formula of a triangle

A = (1/2) * base * height

100

What theorems need to only be continuous

(IVT, EVT)

200

What is the derivative of 12x^5+5x^3+2x^2

60x^4+15x^2+4x

200

lim as h approaches 0 of f(x+h)-f(x)/h what is this called

Definition of derivative 

200

Antiderivative of 3x^4+5x^7

3x^5/5+5x^8/8

200

Cross-section formula of a semicircle

Area = (1/2) * π * r²

200

What theorems need to be both continuous and differential

(MVT and Rolle's)

300

What is the derivative of 9x^2·4x

108x^2

300

lim as x approaches 4 of x^3+2x^2+7x/x-4

71/-4

300

Antiderivative of (3x^2)(8x+3)

6x^4+3x^3

300

Cross-section formula of a trapezoid

A = (1/2) * (a + b) * h

300

Given that f(x) is differentiable f(x)=3x^3+9x^2+5x+4, is there a value c on 0<c<9 such that f(c) = 30 What theorem would be used to solve this

 (IVT)

400

What is the derivative of 5x^3(2x)

40x^3

400

lim as x approaches 5 of (x-9)(2x^3+4x^2+6x)/ x-5

404/5

400

 Integral from 2 to 4 of 3x^4

2976/5

400

Cross-section formula of an equilateral triangle

A = (√3/4) * s²

400

Given that g(x) is differentiable g(x)=2x^3+4x^2+7x+2, is there a value c on 0<c<9 such that g(c) = 42 (Solve)

g(0)=2

g(9)= 1847


Since g(x) is cont as it is dif and 42 is between g(0) and g(9) , by IVT there exists some c value between 0 and 9 such that g(c) = 42

500

What is the derivative of 2x^3+5x^2/7x^3+3x^2

-29/(7x+3)^2

500

lim as x approaches 9  (x^2+5x)(2x^2+4x)(6x+4)/x-9

706740/9

500

Integral from 1 to 5 of 5x^2+6x+2

860/3

500

Cross-section formula of a parallelogram

Area = base * height

500

Let f(x) be a differentiable function with these selected values x(1,2,4,8,14) f(x)(-9,-7,4,9,5)  

Is there a c value, 1<c<11 such that f prime of c is equal to 1 

14-2/5+7 = 1

Since f(x) is dif MVT applies 

Therfore there is a value c from 1<c<14 that exist by MVT