d/dtt^2lnt
2tlnt+t
d/dx(tanx/(1+cosx))
No need to simplify as long as the answer is one fraction
Anything equivalent to
((secx)^2(1+cosx)-tanx(-sinx))/(1+cosx)^2
f(x)=(x^2-1)x(x+5)
f'(x)=3x^2+10x-1
If x = 2, y = 1, and dx/dt = -4, find dy/dt for:
6y^2+x^2=2-x^3e^(4-4y)
dy/dt=8/11
The name of the villain in "The Nightmare Before Christmas"
Oogie Boogie
If y=e^(1/x)/x^2
Then y'=
y'=(-e^(1/x)-2xe^(1/x))/x^4
If f(x)=x^2sin(πx)
Then f'(x)=
2xsin(πx)+πx^2cos(πx)
y=2(6-x^2)^5
y'=10(6-x^2)^4x(-2x)
A rectangle's length is always 3 times its width. If the shorter side is decreasing at a rate of 2 inches per minute, at what rate is the area decreasing? (include units)
The area is decreasing at a rate of 72 square inches per minute.
(Changing at -72 square inches per minute)
another name for a "lycanthrope"
werewolf
d/dt (4log_3t-ln(8t^2))
4/(tln(3))-2/t
d/dxcot(3x^2+5)
-6xcsc^2(3x^2+5)
x^2ln(x)
x(2lnx+1)
20x^2
40x
The author of the 1818 novel, "Frankenstein"
Mary Shelley
d/dx3^(arctan(5x))=
3^(arctan(5x))(ln3)(5/(1+25x^2))
d/dxcsc^2(sinx)=
-2(csc^2(sinx))(cot(sinx))(cosx)
f(x)=(x^2-2)(x^-1+2)
f'(x)4x+2x^-2+1
5x^3 + 10x^2 + 50x
15x^2 + 20x + 50
Rotten Tomatoes lists this movie as the #1 scariest of all time
The Exorcist
If f(x)=(5x)^(3x^2-2x+8)
Then f'(x)=
lny=(3x^2-2x+8)ln(5x)
f'(x)=[(6x-2)ln(5x)+(3x^2-2x+8)(1/x)](5x)^(3x^2-2x+8)
If f(x)=sin(tansqrt(1+x^3))
Then
f'(x)=
f'(x)=cos(tansqrt(1+x^3))(sec^2sqrt(1+x^3))((3x^2)/(2sqrt(1+x^3))
(2x^4-2x^2+2)(5x^4+1)
8x^7-60x^5+48x^3-4x
57x^7-23x^5-15x^3+8x+2
399x^6-115x^4-45x^2+8
The most popular Halloween costume in the US in 2023
Barbie