Quantum Rules & Numbers
Light & Wave Mechanics
Electron Transitions
Configurations & Periodic Trends
Photoelectron Spectroscopy (PES)
100

This quantum number represents the shape of an orbital subshell and ranges from 0 to n-1

angular momentum quantum number (l)

100

In the wave equation c=νλ, as wavelength decreases, this property increases.  

frequency

100

This process occurs when an electron absorbs energy and moves from a lower energy level to a higher energy level.

absorption which is also known as excitation 

100

The full electron configuration 1s2 2s2 2p6 3s2 3p6 belongs to this noble gas.

Argon

100

On a standard PES graph, peak height corresponds directly to this quantity.  

# of electrons in a subshell

200

A set of quantum numbers with n=3, l=3, ml=2, and ms=0 is impossible for what two reasons?

l cannot equal n 

ms cannot be 0

200

 If Photon A has a wavelength of lambda and Photon B has a wavelength of 1/2lambda, Photon B has this much energy relative to Photon A.  

2E or double
200

 When an electron falls from a higher energy level to a lower energy level, a photon is emitted with energy equal to the energy difference.

emission

200

Atomic size decreases across a period from left to right due to an increase in this nuclear force.

Effective Nuclear Charge

200

The element whose PES spectrum ends with the full valence configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

Kr

300

What are the four quantum numbers?

n, l, ml, ms

300

Calculate the wavelength, in nanometers, of light with a frequency of 4.00 x 1014 Hz

750 nm

300

 Between the transitions n=1 -> n=3 and n=2 -> n=3, this transition requires the addition of the most energy

n=1 to n=3

300

Although 7s orbitals are in the 7th period, these d orbitals are located in the 4th period of the periodic table.

3d

300

On a PES graph x-axis, the slashed lines indicate a break or change in scale between these structures

energy levels

400

What is the maximum number of electrons each subshell can hold?

s-2

p-6

d-10

f-14

400

What two constants do we use when calculating light wavelength and energy?

c and h

400

Between n=5 -> n=3 and n=5 -> n=1, this transition results in the emission of the most energy

n=5 to n=1

400

Aluminum has a lower first ionization energy than magnesium because aluminum's outermost electron sits in this subshell.

3p subshell

400

 If you sketch the PES graph for Mg1+, you would modify the neutral Mg graph by making this change to the 3s peak.

have one less electron (cut it in half)

500

The rule stating that electrons fill degenerate orbitals singly before pairing up explains why an Iron (Fe) atom contains this many unpaired electrons.

4

500

High frequency -> _____ wavelengths -> ____ energy

short, high

500

 This level in an atom requires the most energy for an electron to jump away from because it is closest to the nucleus

n = 1

500

 Between Arsenic (As), Silicon (Si), Iron (Fe), and Chlorine (Cl), this element contains the greatest total number of p electrons.  

As

500

The outermost electrons of an atom appear on this side of a PES graph where ionization energy is lowest.

right side of the periodic table