P(A) = .2, P(B) = .75, P(A and B) = .11
Find P(A U B)
P(A U B) = .2 + .75 - .11 = .84
If events A and B are independent, P(A | B) =
Discrete or Continuous?
X = time that students spend on AP Statistics homework
Continuous
X = Random Variable
meanx = .12
sdx = .38
Multiply each X value by 10, find the new mean and sd
1.2, 3.8
The difference between binomial and geometric settings
Geometric is always concerned with the first occurrence of an event happening, while binomial is concerned with a number of successes within a set number of trials
P(A) = .33, P(B) = .4,
Find P(A or B) if events A and B are mutually exclusive
.33 + .4 = .73
60% of elm trees in Fargo get Dutch Elm Disease. If an elm tree gets Dutch Elm Disease, it has to be chopped down 80% of the time. Among elm trees without Dutch Elm Disease, just 5% have to be chopped down.
What is the overall probability that an elm tree in Fargo needs to be chopped down?
Tree Diagram!
0.6*0.8 + 0.4*0.05 = 0.5 or 50%
Let X be a random variable where X = the number of heads flipped in 2 coin flips. Create a probability model for X.
P(X) | .25 | .5 | .25 |
X = $ amount of each size soda (random variable)
meanx = $1.80
sdx = $0.70
Find the new mean and sd if the store increases their prices of soda by $1 each
$2.80, $0.70
Tim makes 80% of his free throws. In a game, he takes 14 free throw attempts. Find the mean and standard deviation of the distribution
mean = (.8)(14)
SD = sqrt(14x.8x.2)
P(A) = .5, P(B) = .75
Find P(A and B) if the events are independent.
.5*.75 = .375
In probability notation, write out the following: the probability that a randomly selected student in the room is wearing a sweatshirt, given that student is boy.
P(sweatshirt|boy) = P(sweatshirt and boy) / P(boy)
Find the expected value for the game:
Roll a six-sided die,
If you roll a 1, win $10
If you roll a 2, 3, or 4, lose $15
If you roll a 5, win $20
If you roll a 6, win $50
10*(1/6) + -15*(3/6) + 20*(1/6) + 50*(1/6)
= $5.83
Let A and B be random variables
meanA = 6.4
meanB = 8.9
Find meanA and B
15.3
You take a 30 question multiple choice test (choices A-D for each question), and unfortunately know nothing on it. If you were to guess on every question, what is the probability that you get 5 questions correct?
binomialpdf(30,.25,5)
30 C 5 * (0.25)^5 * (0.75)^15
.1047
P(A) = .20, P(B) = .39
Find P(A or B) if events A and B are independent
.20 + .39 - (.20*.39) = .512
Find the probability that a card randomly selected from a standard deck is a queen, given the card is black.
2/26
= .077
Let X = height of students at FNH, in inches, and the distribution is approximately normal. If the mean and standard deviation are 52 and 4.7, respectively, find the probability that a randomly selected student would be taller than 60 inches.
.0444
X and Y are Random Variables
sdx = 8
sdy = 7
Find sdx-y
sqrt(113) = 10.63
A wide receiver has a catch rate of 40%. What is the probability that his first catch will be on or before his 3rd target?
0.4 + 0.6*0.4 + 0.6*0.6*0.4
= 0.784
If two events, A and B, are mutually exclusive, what can we say about their independence?
A) They are independent
B) They are not independent
C) One cannot determine whether or not they are independent
B) They ARE NOT independent. If A and B are mutually exclusive, knowing that A has happened then makes it impossible for B to happen. Thus, A occurring influences the likelihood of B occuring.
In a bag of 20 flower seeds, 15 will produce a flower, and 5 are duds. Find the probability that the first seed that is a dud is the fourth one you pick without replacement.
(15/20)*(14/19)*(13/18)*(5/17)
= 0.117
Find the expected value AND standard deviation for the random variable X = years taken to graduate at NDSU.
X | 3 | 4 | 5 | 6 | 7 |
P(X) | 0.1 | 0.5 | 0.1 | 0.2 | 0.1 |
Expected value: 4.7 years
Standard deviation: 1.1874
Let U and V be random variables that are approximately normally distributed.
meanu = 500, sdu = 15
meanv = 200, sdv = 8
Let T = U + V, find P(T > 717)
.16
You are able to talk Mr. Lehman into extending a homework assignment 95% of the time. Out of 10 homework assignments, what is the probability that you can talk him out of at least 9 of them?
0.913
(I'm not even going to attempt to type in the work)