Excluded Values
Find the excluded values for the expression
\frac{1}{x-3}
x = 3
Simplify the expression
\frac{x^2 - 9}{x - 3}
x+3
\frac{2x}{3} \cdot \frac{3}{4x}
\frac{1}{2}
\frac{x}{x-1} \div \frac{1}{x+1}
\frac{x(x+1)}{x-1}
\frac{2}{x} + \frac{3}{x}
\frac{5}{x}
\frac{x+2}{x^2 - 4}
x = 2, x = -2
Simplify the expression:
\frac{x^2 - 4}{x^2 + 4x + 4}
\frac{(x-2)(x+2)}{(x+2)^2} to \frac{x-2}{x+2}
\frac{3x}{x-3} \cdot \frac{x-3}{x+3}
\frac{3x}{x+3}
\frac{x^2 - 1}{x+2} \div \frac{x-1}{x+2}
\frac{x+1}{1} to x+1
\frac{x}{x+1} - \frac{2}{x+1}
\frac{x-2}{x+1}
\frac{2x+1}{x^2 - x - 6}
x = 3, x = -2
\frac{x^2 - 16}{x^2 - 4x}
\frac{(x-4)(x+4)}{x(x-4)}to \frac{x+4}{x}
\frac{x^2}{x^2 - 9} \cdot \frac{3}{x}
\frac{3x}{x^2 - 9}
\frac{2x}{x+3} \div \frac{x^2}{x^2+5x+6}
\frac{2x(x+2)}{x^2} to \frac{2(x+2)}{x}
\frac{x+2}{x-1} + \frac{x-3}{x-1}
\frac{2x-1}{x-1}
\frac{x^2 - 1}{x^2 - 5x + 6}
x = 2, x = 3
\frac{2x^2 + 8x}{4x^2 + 8x}
\frac{2x(x+4)}{4x(x+2)} to \frac{x+4}{2(x+2)}
\frac{x^2 - 1}{x+1} \cdot \frac{x+1}{x^2 + x}
\frac{x-1}{x}
\frac{x^2 + 3x}{x^2 - 4} \div \frac{x}{x-2}
\frac{x(x+3)(x-2)}{x(x+2)(x-2)} to \frac{x+3}{x+2}
\frac{3x}{2x+6} - \frac{2x}{x+3}
\frac{x}{x+3}
\frac{x^2 + 5x + 6}{x^3 - 4x}
x = 0, x = 2, x = -2
\frac{x^2 - 6x + 9}{x^2 - 3x}
\frac{(x-3)^2}{x(x-3)} to \frac{x-3}{x}
\frac{x^2 + x}{x^2 - 4} \cdot \frac{x-2}{x+1}
\frac{x}{x+2}
\frac{x^2 - 9}{x^2 + x} \div \frac{x-3}{x+1}
\frac{x+3}{x}
\frac{x}{x+1} + \frac{1}{x}
\frac{x^2 + x + 1}{x(x+1)}