lim as x approaches 0 for the function f(x)=(6x+4)/(3x-1)
-4
the derivative of the function f(x)= (x^8)+13(x^6)-6(x^3)+x+19
8(x^7)+78(x^5)-18(x^2)+1
the left Riemann sum for the function f(x)=3x+2 between x=0 and x=5 and using 5 rectangles is
40
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The function above has a positive derivative between the x values:
[0,2]
A 13 foot ladder is slowing sliding down a wall at a rate of .5 ft/ second. Before the ladder starts sliding down the wall, the ladder's tip is 12 feet from the floor. At what rate is the base sliding horizontally when the height from the floor is 7 feet?
6/5 ft/sec
lim as x approaches infinity of the function f(x)= (10x+3)/(5x-9)
2
the derivative of the function f(x)=(2(x^3)+3)/(3x-4) is
12(x^3)-24(x^2)-9 / (3x-4)^2
42
when the graph of a particle in motion has a negative derivative and a negative second derivative at t=a, the particle is
speeding up
The characteristics that define a function as differentiable are
continuous and has a definitive derivative at all points
lim as x approaches 3 of the function f(x)=(2(x^2)-x-15)/(x-3)
11
find the tangent line of the function f(x)=sin(pi*x)+1 at x=1
y-1=pi(x-1)
the area between the functions f(x)=(x^2)+3 and g(x)=0.5x+10 is
25.025
the function f(x)=(x+2)^3/ (x-5) is concave up between the interval
(-infinity, -2)U(5, infinity)
when a particle who's motion is represented by a function has an f(a)' that is positive and f(a)'' is negative, the particle is
slowing down
lim as x approaches 1 of the function f(x)=((x^3)-1)/(x-1)
3
the derivative of the function f(x)=ln(3(x^2)+9)^1/2
x/(x^2)+3
the change in position of a particle, which is represented by the function v(t)= 5x+4, between t=2 and t=10 is
272 units
the inflection points of the function f(x)=(x+3)^3 + x^2 are
x= (-10/3), (299/27)
the implicit derivative of the function 2(x^2)y+5y^2=7x is
dy/dx= (7-4xy)/(2(x^2)+5y)
the values for a and b that make the function f(x)= a-4x(x<1) and (x^2)+b (x>/=1) continuous are
a=7
b=2
the dy/dx of the equation 2(x^2)+2(y^2)=8 is
-x/y
the volume of a shape created by revolving the function f(x)=3(x^2)+8x-7 from x=0 to x=3 around the x axis is
120.4*pi units^3
the tangent line for the function f(x)=-3(x^3)+2(x^2)+8x+2 at x=2 is
above the curve
the derivative of the function f(x)=tan(pi+x)3(x^2)
6xtan(pi+x)+3(x^2)sec^2(pi+x)