Integration
Disks & Washers
Shells & Slicing
Work (Springs & Ropes)
Inverse + Log/Exp
100

∫2xcos(x2)dx

sin(x2)+C

100

the volume when y=x2, from 0 to 1, rotated about the x-axis.

π/5

100

When should you use shells instead of washers?

when slicing parallel to axis of rotation or when solving for the other variable is messy.(draw picture)

100

Hooke's Law (spring) F=

F=kx

100

Derivative of ln⁡x

 ∫exdx

1/x

ex+c

200

∫1/(xlnx)dx

ln∣lnx∣+C

200

the volume when y=x2, from 0 to 1, rotated about the y-axis

π/2

200

Rotate y=x2, 0→1, about y-axis (shells)

π/2  

200

Spring stretched 2m with force 10N → find k

5

200

Derivative of e3x

∫1/xdx 

3e 3x

ln∣x∣+C

300

∫xe(x^2)dx

1/2e^x^2+C

300

Region between y=x and y=x2, rotated about x-axis

2π /15

300

shell setup

V=2π∫(radius)(height)dx

300

Work to stretch a spring (k=5) from 1m to 3m

20

300

(f−1)′(a)

∫e2xdx

1/(f′(f−1(a)))

1/2e2x+C 

400

∫x/(sqrt(1+x2))dx

sqrt(1+x^2)+C 

400

the washer setup

& the washer setup key

V=π∫(R2−r2)dx

outer radius − inner radius

400

slices impact

  • Perpendicular slices → disks/washers
  • Parallel slices → shells 
400

A rope of length 10 m hangs over the side of a building. The rope has a mass density of 2 kg/m. How much work is required to pull the entire rope up to the top?

980 J

400

Differentiate: y=ln⁡(x2+1)


2x/(x2+1)

500

∫sin3xcosxdx

(sin4x)/4 +C

500

Switch to x=sqrt(y)

V=π∫(R2−r2)dy

500

Compare slicing vs shells; which is easier and why?

  • function is already in terms of x
  • avoids solving for inverse 
  • when slicing parallel to axis of rotation 
  • when solving for the other variable is messy.
500

A bucket containing 20 kg of water is lifted 10 m to the top of a building. The bucket itself weighs 5 kg. As it is lifted, water leaks out at a constant rate, so that by the time it reaches the top, the bucket is empty. How much work is done?

1470 J

500

Differentiate: y=xx 


xx(lnx+1)