Basic Derivatives
Product and Quotient Rule
Chain Rule
Implicit Differentiation
Trigonometric Differentiation
Inverse
Trigonometric
Differentiation
Natural Logarithms and Exponentials
tangent lines &
normal lines
100

What is the derivative of

y = 3x^2

 ?

y' = 6x

100

Find the derivative of 

y = 3x^2 sin x

3x^2 cos x + 6x sin x

100

Find y' if

y = (3x - 9)^4

12(3x - 9)^3

100

Find the derivative implicitly

x^2 + y^2 = 30

y' = - x/y

100

Find the derivative of

f(x) = 3sinx - 2cosx

3cosx + 2sinx

100

cos^(-1)x^3

-(3x^2)/(sqrt(1-x^6)

100

ln4x^3

3/x

100

what is the slope of the tangent line? the tangent line is 

5x-2.5=-2(y+3)

slope = 

-5/2

200

Find the derivative of 

f(x) = 5

0

200

f(x) = (3x - 2x^2)(5 + 4x)

-24x^2 + 4x + 15

200

Find the derivative of 

f(x) = sin 4x

4 cos 4x

200

sin x + 2cos 2y = 1

y' = cosx/(4sin2y)

200

y=csc3x^5

y'=-15x^4csc3x^5cot3x^5

200

sin^-1(-x^2)

-(2x)/sqrt(1-x^4)

200

y=e^(sinsqrtx)

cossqrtx/(2sqrtx )(e^sinsqrtx)

200

what is the normal line of 

f(x)=-1/2x^2+2x+1

y=1(x-3)+2.5

300

Find the derivative of 

f(x) = 6x^3 + x - 2

18x2 + 1

300

Find the derivative of 

y = (5x - 2)/(x^2 + 1)

(-5x^2 + 4x + 5)/(x^2 + 1)^2

300

Find y' if 

y = (9x^2 + 4)^(1/3)

(6x)/(9x^2 + 4)^(2/3

300

(y - 2)^2 = 4x - 12

y' = 2/(y - 2)

300

y=sec5x^5

y'=25x^4sec5x^5tan5x^5

300

cot^-1 4x^2

-(8x)/(16x^4+1)

300

f(x)=sqrt(5+e^(2x)

e^(2x)/sqrt(5+e^(2x)

300

write the equation for the normal line to 

f(x)=(1+x)^(-1/2), x=3

y=16(x-3)+1/2

400

 h(x)=f(x)*g(x), h'(3)= ? 

15-8pi

400

Find the derivative of 

f(x) = (2x + 5)/(x)^(1/2)

(2x - 5)/(2x^(3/2)

400

f(x) = sin^3 4x

Find f'(x)

12sin^2 4x cos 4x

400

x^3 - 3x^2y + 2xy^2 = 12

y' = (-3x^2 + 6xy - 2y^2)/(-3x^2 + 4xy)

400

w(x)=g(x)sinx, w'(0)=?

pi/2

400

tan^-1 -x^5

-(5x^4)/(x^10 +1

400

y=3^(x^2-1)

2xln3(3^(x^2-1))

400

Write the equation for the tangent line when (2,1)

x^2y+y^2x=6

y'=5/8(x-2)+1

500

Find the third derivative of 

5x^5+2x^2+4x

300x^2

500

Find the Derivative of 

y= (2x+1)/(2x-1)

y'=-4/(2x-1)^2

500

Find 

f'(theta)

f(theta)=secsqrt(theta)

(secsqrt(theta)tansqrt(theta))/(2sqrt(theta))

500

x^2y+y^2x=6

y'=(-2xy-y^2)/(x^2+2xy)

500

y=x^3tanx

y'=x^3sec^2x+3xtanx

500

y=sin^(-1)(x/3)

1/(3sqrt(1-x^2/9)

500

g(x)=4xlnx

4+4lnx

500

if 5x^2+2x^2y+y^2=8

 then y' at the point (1,1) is?

y'=-7/2