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Slippery Slope
Integreat!
A Slice of Pi
Calculus Rules!
Tigger's Functions
100
d/dx x²
2x
100
∫ 3x dx
(3/2)(x^2) +C
100
sin(0)
0
100
Let f be continuous on [a,b] such that x is in a point in [a,b] Let F(x) = fnInt(f(t), t, a, x) F'(x) = f(x)
1st Fundamental Theorem of Calculus
100
1/tan(x)
cot(x)
200
d/dx x³+x-1
3x² + 1
200
∫ xcos(x^2) dx
(1/2)sin(x^2)+C
200
cos(π)
-1
200
Let f and F be continuous on [a,b] and let F be an antiderivative of f fnInt(f(x), x, a, b) = F(b) - F(a)
2nd Fundamental Theorem of Calculus
200
sin(x)/cos(x)
tan(x)
300
d/dx (x^5)(sec(x))
(5x^4)(sec(x))+(x^5)(sec(x)tan(x))
300
∫(x^5-6x+3) dx
((x^6)/6)-(3x²)+3x+C
300
tan(π)
0
300
If f is continuous on [a,b], then f has both a global (absolute) maximum and minimum value on [a,b]
Extreme Value Theorem
300
sin(2x)
2sin(x)cos(x)
400
d/dx (cos(x^5))^6
-(30x^4)(cos(x^5))^5)(sin(x^5))
400
∫((x^3)-(1/x^3))
(x^4)/4+(1/2x²)+C
400
tan(π/2)
undefined
400
∫udv = uv - ∫vdu
Integration by Parts
400
1/csc(x)
sin(x)
500
log2(2x²)
(1/ln(2))(2/x)
500
∫sec^2(x) dx
tan(x)+C
500
cos(π/6)
√(3)/2
500
Let f be continuous on some closed interval [a,b]. If d is between f(a) and f(b), then there exists some c between a and b such that f(c) = d
Intermediate Value Theorem
500
1-(cos(x))²
(sin(x))²