This entropy can never decrease.
What is the entropy of the universe?
List 3 differences between the equilibrium dependent equations of ΔGo and ΔGrxn.
ΔGo depends on K and is calculated with a negative sign. ΔGrxn is calculated with Q and is dependent on ΔGo.
Fill in the blanks: During reduction, we ______ electrons. During oxidation, we ______ electrons.
Gain, lose
Which is the correct Equation?
a. ΔSuni=ΔSsys + ΔSsurr
b. ΔSsys = ΔSuni + ΔSsurr
c. ΔSuni = ΔSsys - ΔSsurr
d. ΔSsurr = ΔSuni - ΔSsys
A and/or D.
Determine the signs of ΔSo and ΔHo for the combustion of propane given the following equation:
C_3H_8(g)+5O_2(g)->3CO_2(g)+4H_2O(g)
Why is ΔSo positive and ΔHo negative?
This is the oxidation state of O2. Explain why.
How much is 0 because O2 is an element.
Does absolute molar entropy increase or decrease with molecular complexity? Why?
Molar entropy increases with molecular complexity because energy can have a larger distribution over more molecules/bonds.
When the sign for ΔHo is positive and the sign for ΔSo is negative, this will be the for ΔGo.
What is positive?
These are the steps to balancing a redox reaction in a basic solution.
(Does not need to be answered in the form of a question, but extra 50 points if you can)
How do you separate into half reactions, balance all elements except oxygen, add in electrons, balance charges with hydroxide, balance oxygen with water, and then combine to cancel the electrons?
The standard molar entropy for diamond is 2.4 J/mol K. Calculate the number of microstates available to a single carbon atom in diamond, and the number of available microstates for one mole of carbon atoms in diamond.
(Double Jeopardy)
Part I: 1.322 microstates available per atom
Part II: e1.74*10^23 microstates available per mole
Calculate the change in entropy that occurs in the surroundings when acetone (C3H6O) freezes at its melting point (-87.4 degrees C) ΔHfus for acetone is 4.20 kJ/mol.
22.6 J/mol*K
Determine which element is going through reduction/oxidation. CO + I2O5 -> CO2 + I2
Calculate W for a system where you have five particles. Two of the particles must have 9 J of energy, one must have 5 J, one must have 3 J, and the other must have 10 J.
What is W=60?
The standard free energy change for the hydrolysis of ATP is -30.5 kJ.
ATP(aq)+H2O(l)→ADP(aq)+Pi(aq)
In a particular cell, the concentrations of ATP, ADP, and Pi are 0.0028 M , 0.0014 M , and 0.0047 M , respectively. Calculate the free energy change for the hydrolysis of ATP under these conditions. (Assume a temperature of 298 K.)
-45.5 kJ or -4.55*104 J
Balance the Following Reaction in Base:
C6H12O6(aq) + VO4 3−(aq) -> CO2(𝑔) + V2+(aq)
(Double Jeopardy)
C6H12O6(aq) + 8VO4 3−(aq) +14H2O(l)-> 6CO2(𝑔) + 8V2+(aq)+40OH-(aq)