Vocab
Critical Values
CI for Prop
CI for Means
Random
100

A ____ is a number that describes some characteristic of a sample. 

Statistic

100

If you were constructing a CI for proportions, find z* for a 95% confidence level. 

1.96

100

Form a conclusion for the 95% confidence interval, (0.073, 0.124), which represents the proportion of students who were tardy to school. 

We are 95% confident that the interval from 0.073 to 0.124 captures the true proportion of all students who are tardy to school.

100

We want to find the average premiums paid on life insurance policies. So, we take a random sample of 45 life insurance policy holders and calculate the average paid. Determine if the conditions for means have been met. 

Random - Yes! "random sample of 45..."

Large - Yes! 45 > 30

100

When the sample size is increase, the margin of error _________. 

DECREASES!

200

p is used to represent ___________

population proportion

200

If you were constructing a CI for proportions, find z* for a 97% confidence level.

2.17

200

A student wants to estimate what proportion of her peers are going into a 2-year program. She takes an SRS of 50 students and found 14 of them plan on enrolling in a 2-year program. Check if the conditions for proportions have been met. 

Random - yes! SRS

Large counts - Yes! np=14, n(1-p)=36 >10 

200

How much time do students spend on homework? You collect data from your 20 classmates and calculate the mean amount of time that each student spent on homework. Check if the conditions for means have been met. 

Random - NO, classmates are not random


Large - NO 20 < 30

200

Given the interval (15.2, 16.8), find the point estimate and margin of error. 

PE = 16, ME = 0.8

300

The_____ gives the long run success rate of confidence intervals calculated with C% confidence. 

Confidence Level C

300

What critical value t* should be used in constructing a 90% CI for mean when n=30? Round to 3 decimal places. 

1.699

300

Of 367 randomly selected students, 30 said that they planned to work in a rural community. Find a 95% confidence interval for true proportion. 

(0.054, 0.110)

300

A 95% confidence interval for the true mean weight of all packages received by a parcel service was found to be (29.59, 31.61). Write up a conclusion for such interval. 

We are 95% confident that the interval 29.59 to 31.61 captures the true mean weight of packages received by the parcel service. 

300

At a swim meet, 8 different swimmers complete in the 800 meter freestyle race. How many different ways are there for these swimmers to finish? 

40,320

400

The _____ of an estimate describes how far, at most, we expect the point estimate to vary from the true population value.

Margin of Error

400

What critical value t* should be used in constructing a 95% CI for mean when n=85? Round to 3 decimal places. 

1.989

400

In a telephone poll of 1012 adult Americans, 11% of the respondents said that Regan was a great president. Give a 98% confidence interval for the proportion of all adult Americans who think Regan was great. 

(0.087, 0.133)

400

A laboratory tested 83 smoothies from the mega menu at Smoothie Uniiverse and found that the sample mean number of calories was 233 and sx=12.9 ounces. Construct a 95% confidence interval for the true mean of calories of all such smoothies. 

(230.183, 235.817) 

400

At the beginning of the chapter, Coach Drown said matching symbols would be on the test. How many did she say would be on the test? 

5! (out of a total of 7 that were given)

500

The ____ is a multiplier that makes the interval wide enough to have the stated capture rate.

Critical Value

500

What critical value t* should be used in constructing a 98% CI for mean when n=22? Round to 3 decimal places

2.518

500

A survey of 300 students reveals that 112 favor year round school with two week vacations every ten weeks. Construct a 98% CI for the true proportion of all students who favor year round school. Complete the FULL 4_STEP PROCESS

98% CI for proportion of all students who favor year round. 

Random - yes, Large - np=112, n(1-p)=188>10 yes

(0.308, 0.438)

We are 98% confident that the interval 30.8% to 43.8% captures true proportion of students in favor. 

500

A group of 67 randomly selected lifeguards from Orange County, CA have a mean age of 24.6 with a standard deviation of 2.5 years. What is the 90% confidence interval for the mean age of all lifeguards from Orange County? Complete the FULL 4-STEP PROCESS

90% CI for true mean age of OC lifeguards.

Random - yes, Large - 67>30 yes

(24.09, 25.11) 

We are 90% confident that the interval 24.09 to 25.11 captures the true mean age of OC lifeguards.

500

What is Coach Drown's middle name?

Rose