Formulas
Point Estimate/Error
Normal/Uniform
Proportions
Means
100

point estimate & margin of error for mean (Population St. Dev. Known)

Point Estimate:  hatx = (sumx)/n 

Margin of Error: E = Z_c *sigma/sqrtn 


100

Find the point estimate based off of the following information:

 99% Confidence level, n= 827, x=174

Round to 4 decimal places

 0.2104

100

A continuous uniform distribution has outcomes between 1 to 19,  find

P(6<x<12)

6/18 = 1/3 or .3333...

100

In a telephone poll of 1012 adult Americans, 11% of the respondents said that Regan was a great president. Give a 98% confidence interval for the proportion of all adult Americans who think Regan was great. 

(0.087, 0.133)

100

A laboratory tested 83 smoothies from the mega menu at Smoothie Uniiverse and found that the sample mean number of calories was 233 and sx=12.9 ounces. Construct a 95% confidence interval for the true mean of calories of all such smoothies. 

(230.183, 235.817) 

200

point estimate & margin of error for proportions 

Point Estimate:  hatp =x/n 

Margin of Error: 

E = Z_c *sqrt((hatp hatq)/n)


200

Find the point estimate of the proportion of people who enjoy reading, in a random sample of 749 people, 61 enjoyed reading.

“p-hat”=0.08

200

A normal distribution has a mean of 64 and a standard deviation of 3.2, find and round to 4 decimal places.

P(x<60)

10.56% or .1056

200

Of 367 randomly selected students, 30 said that they planned to work in a rural community. Find a 95% confidence interval for true proportion. 

(0.054, 0.110)

200

Suppose you want to construct a 95% confidence interval for the average speed that cars travel on the highway. You want a margin of error of no more than plus or minus 0.5 mph and know that the population standard deviation is 7 mph. At least how many cars must you clock?

 n=753

300

Given the confidence interval, the formula for 

hatp and E 

hatp = (upper + lower)/2

E = (upper -lower)/2

300

A confidence interval was constructed to estimate the proportion of smokers in the U.S. Use the confidence interval 0.167 < p < 0.458 to find the margin of error, E. Round answer to 3 decimal places.

E=0.146

300

The heights of a group of seven-year-old children are normally distributed with mean 117 cm and standard deviation 5 cm. A child is chosen at random from the group.

The probability that this child is shorter than k cm is 0.65. Find the value of k.

What is 119?

300

 Suppose you want to construct a 90% confidence interval for the proportion of people who will stop to pick up a nickel if they see one on the ground. You want a margin of error of no more than plus or minus 4 percentage points. How many people must you survey?

n=423

300

 Construct a 92% confidence interval of an experiment that found the mean temperature for the city in August was 101.82, with a population standard deviation of 1.2. There were 6 samples in this experiment.

100.96 < μ < 102.68