Ordered pairs and Intercepts
The intercepts of the graph of 3x+7y=21
x-int: (7,0)
y-int: (0,3)
Find the center-radius form of the equation of the circle:
Center (1,0) radius=4
(x-1)^2 +y^2=16
Find the slope and y-intercept of the line:
y=5x-1
m=5
y-int: (0,-1)
1.List the (a)Domain, (b)Range, (c)Keypoint, (d)shape of the function: y=|x|
2. List/write the equation
1. (a)Domain: (-inf,inf); (b)Range: [0,inf); (c)Keypoint: Vertex; (d) V-shaped graph
2. f(x)=a|x-h|+k
f(x)=5x^2+4 and g(x)=-4x+1
Find (f-g)(-4)
(f-g)(-4)=67
Intercepts of the graph of 3x+2y=6
x-int: (2,0)
y-int: (0,3)
Find center-radius form of the equation:
Center (-1,4) radius=3
(x+1)^2+(y-4)^2=9
Find the slope and y-intercept of the line:
4x-y=2
m=4
y-int: (0,-2)
1. List the (a)Domain, (b)Range, (c)Keypoint, (d)shape of the function: y=x^2
2. List/write the equation
1. (a)Domain: (-inf,inf); (b)Range: [0,inf); (c)Keypoint: Vertex; (d) U-shaped graph
2.f(x)=a(x-h)^2+k
f(x)=x-1 and g(x)=x^2-x
Find (f+g)(4)
(f+g)(4)=15
The intercepts of the graph y=x^2 -9
x-int: (3,0) & (-3,0)
y-int: (0,-9)
Find the center and radius from the equation:
(x-2)^2+(y-3)^2=4
Center (2,3) radius=2
Write an equation for the line passing through (-2,1) & (3,2)
x-5y=-7
1. List the (a)Domain, (b)Range, (c)Keypoint, (d)shape of the function: y=x^3
2. List/write the equation
1. (a)Domain: (-inf,inf); (b)Range: (-inf,inf); (c)Keypoint: Point of inflection; (d) 1/2 up and 1/2 down parabola
2. f(x)=a(x-h)^3+k
f(x)=x^2-8 and g(x)=10-x
Find (f/g)(1)
(f/g)(1)=-7/9
to find a y-intercept we?
to find an x-intercept we?
set x=0 to find a y-intercept
set y=0 to find an x-intercept
Find the center and radius from the equation:
x^2+y^2+10x+2y+17=0
Center(-5,-1) Radius=3
Write an equation in slope-intercept form through (-1,5) and parallel to x+2y=5
y=-1/2x+9/2
1. List the (a)Domain, (b)Range, (c)Keypoint, (d)shape of the function: y=√x
2. List/write the equation
1. (a)Domain: [0,inf); (b)Range: [0,inf); (c)Keypoint: Starting point; (d) Curved arrow
2. f(x)=a(√x-h)+k
f(x)=7x-3 and g(x)=3x-7
(a)Find (FoG)(x)
(b)Find (GoF)(x)
a) (FoG)(x)=21x-52
b)(GoF)(x)=21x-16
The origin is this ordered pair
the origin is (0,0)
Find the center and radius of the graph:
x^2+y^2+4x-8y+21=0
The graph is nonexistent
because (x+2)^2+(y-4)^2=-1 cannot be graphed
Write an equation in slope-intercept form through (1,6) and perpendicular to 2x+5y=1
y=5/2x+7/2
Is x=y^2 considered a function? Why or why not?
Not a function. Does not pass the vertical line test
f(x)=2x+3 and g(x)=x-5
(a)Find (fg)(x)
(b)Find (f/g)(x) and state domain restrictions **AKA:excluded values**
(c)Find f(6)
a) (fg)(x)= 2x^2-7x-15
b) (f/g)(x)= (2x+3)/(x-5)
All real numbers except x=5 [x cannot =5]
(-inf,5)U(5,inf)
c) (6,15)