d/dx sin(x)
cos(x)
What rule to solve d/dx 5x?
Constant Rule
y=(cosx)7
((-7sinx)/(cosx))((cosx)7)
find the slope x2 +y2=25 at (3,-4)
3/4
When do you use logarithmic differentiation?
Whenever you want (products + quotients)
d/dx tan(x)
sec^2 x
3x-arcsinx
derivative of 3x subtracted by derivative of arcsinx
use logarithmic. x3y+y2-x2=5
-4/5
find dy/dx given y2 =3xy+siny
dy/dx=3y/(2y-3x-cosy)
Another word for derivative
instantaneous slope
d/dx lnx
1/x
What is the overarching rule used to find the derivative without logarithmic differentiation? ((5x-50/x)(arctanx+2x))/(19sin(cos(x)))
Quotient Rule
y=x3⋅e2x, find dy/dx. use implicit differentiation.
dy/dx = 3x2 e2x+2x3e2x
Find (dy/dx) given x2y + xy2 =6
(2xy + (y^2))/(x^2) +2xy
What is differentiation
The act of finding the derivative
d/dx cot^-1 x
-1/1+x^2
How can you solve this problem without using quotient rule: (x5-2x3-8x2)/x
Simplify then use the power rule.
y= sqrt(x)⋅ln(x). use logarithmic differentiation.
dy/dx = (1+2ln(x))/2sqrt(x)
Find the tangent line at xsin2y = ycos2x
at (pi/4, pi/2)
y- (pi/2) = 2(x- (pi/4))
Which one would you use the product rule for?
9(x+1) or x(x +1)
x(x+1)
d/dx csc^-1 x
-1/(|x|sqrt(x^2 -1))
How could you solve this problem without using quotient rule or logarithmic differentiation: sinx/3x2
Product Rule. Manipulate the equation to make it sinx(3x-2) then you can do the normal operations for product rule.
sin2x2y3= 3x3+1. Find dy/dx using implicit.
dy/dx = (9x-4y3cos2x2y3)/(6xy2cos2x2y3)
Find the normal and tangent line at x2 +xy -y2=1
at (2,3)
Tangent: y-3= (7/4)(x-2)
Normal: y-3= (-4/7)(x-2)
Difference between implicit and explicit differentiation
Implicit: y is wrapped up into problem
Explicit: Gives us y clearly