500
What mass, in grams, of hydrogen is produced from the reaction of 4.73 g of Mg with 1.83 g of H2O?
Mg + 2H2O --> Mg(OH)2 + H2
0.102 g
H2O is the limiting reagent, which is necessary information to solve this problem. 0.102 mol of H2O are used up, and using the mole to mole ratio, we then know that HALF of that (0.051 mol) of H2 is formed in the products. Using molar mass, 0.051 mol of H2 equals 0.102g of H2.