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Molarity
Balancing
Stoichiometry w/ bonus question
100

How many mL of 3.5M HCl contain 1.21 x 10-3 moles?

0.35 mL

100

If the following equation is balanced, what is the coefficient in front of Al?

Al2O3 --> Al + O2

4

100
How many grams of rust (159.7 g/mole) are formed when 5 moles of Fe react with excess of other reactants?

4Fe + 3O2 --> 2Fe2O3

399.25 g

200

How many mL of 1.6M HCl is needed to make 500 mL of 0.38M HCl?

118.75 mL

200

If the following equation is balanced, what is the coefficient in front of AlCl3?

AlBr3 + Cl2 --> AlCl3 + Br2

2

200

If 308 g of rust (159.7 g/mole) are formed, how many grams of oxygen (32 g/mole) reacted with excess iron?

4Fe + 3O2 --> 2Fe2O3

92.6 g

300

Describe how you would prepare 150 mL of a 5.4M NaOH solution using a stock bottle a concentration of 12.0 M.

Take 67.5 mL of the stock solution and dilute with water to 150 mL.

300

If the following equation is balanced, what is the coefficient of O2?

S8 + O2 --> SO2

8

300

If 5850 g of Bi2O3 (466 g/mole) react with 415 g of C (12 g/mole), how many moles of CO (28 g/mole) are formed?

Bi2O3 + 3C --> 2Bi + 3CO

968.3 g CO

400

How would you make 150 mL of a 5.4M solution of NaOH using solid NaOH?

Dissolve 32.4g of NaOH in 150 mL of water.

400

If the following equation in balanced, what is the sum of all the coefficients? 

P4 + O2 --> P2O5

8

400

If 5850 g Bi2O3 (466 g/mole) and 415 g C (12 g/mole) form 34.6 moles of CO, how many grams of excess reactant are left?

Bi2O3 + 3C --> 2Bi + 3CO

475.47 g Bi2O3 

500

How many mL of 2.25M HF are needed to react if 3.891 kg of UF4 (314 g/mole) form? 

UO2 + 4HF --> UF4 + 2H2O

22029.72 mL

500

When the following equation is balanced, what is the sum of all the coefficients?

Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 + CaSO4

9

500
Describe total ionic equations, net ionic equations, and spectator ions.

*discussion*