400
Quantities of PCl3 and Cl2 were placed in a reaction chamber and heated to 503 K at 1 atm. At equilibrium, Keq= 0.0205; and [PCl5] = 0.235 and [PCl3] =0.174. Calculate the concentration of Cl2. PCl5(g) (Reverse Reaction) PCl3(g) + Cl2(g).
What is 0.0205 = [PCl3][Cl2]/[PCl5][Cl2] =(0.0205)(0.235)/0.174 = 0.0277 M