Atoms and Mole
Acids & Bases
Stoichiometry
Bonds and Periodic table
Real life chemistry
100

Define 1 mole in terms of Avogadro’s number.

1 mole = 6.022×10²³ particles.

100

What is neutralization?

Reaction between acid and base to form salt + water.

100

Balance: CH₄ + O₂ → CO₂ + H₂O.

CH₄ + 2O₂ → CO₂ + 2H₂O.

100

Most reactive alkali metal?

Francium (but practically Cesium).

100

Why add lime (CaO) to soil?

Neutralizes acidic soil.

200

How many moles are in 36 g of H₂O?

36 g ÷ 18 g/mol = 2 mol.

200

Write balanced equation for HCl + NaOH.

HCl + NaOH → NaCl + H₂O.

200

What is the limiting reagent?

Reagent that is fully consumed first in a reaction.

200

Why does fluorine have highest electronegativity?

Smallest size, high nuclear charge → strong attraction.

200

Which ion in acid rain causes corrosion?

H⁺ (from H₂SO₄, HNO₃).

300

Convert 0.5 mol NaCl into number of formula units.

0.5 × 6.022×10²³ = 3.01×10²³ formula units.

300

25.0 mL of 0.100 M HCl neutralizes how many moles NaOH?

0.025 × 0.100 = 0.00250 mol NaOH.

300

10 g H₂ reacts with 80 g O₂. Mass of H₂O formed?

10 g H₂ = 5 mol; 80 g O₂ = 2.5 mol. Limiting O₂ → 5 mol H₂O = 90 g.

300

Draw Lewis structure for CO₂.

O=C=O (linear).

300

How does an antacid tablet work?

Neutralizes stomach HCl.

400

44.8 L of CO₂ at Standard Temperature and Pressure equals how many moles?

44.8 L ÷ 22.4 L/mol = 2 mol.

400

40.0 mL of 0.200 M H₂SO₄ neutralizes 60.0 mL NaOH. Find NaOH molarity.

Moles H₂SO₄ = 0.040×0.200 = 0.008. Needs 0.016 mol NaOH. 0.060 L used → 0.016/0.060 = 0.267 M.

400

A reaction is predicted to produce 25 g of NaCl (theoretical yield), but in the lab, only 20 g is obtained (actual yield).
What is the percent yield of the reaction?

Percent Yield=Theoretical Yield/Actual Yield×100 =20/25×100=80%

400

Difference between ionic & covalent bonding.

Ionic: electron transfer. Covalent: electron sharing.

400

Why is water a universal solvent?

Polar → dissolves many solutes.

500

A compound contains 40% C, 6.7% H, 53.3% O. Find empirical formula.

CH₂O.

500

Diprotic acid requires 30 mL 0.200 M NaOH for 25 mL solution. Find acid molarity.

Moles NaOH = 0.030×0.200 = 0.006. Diprotic → 0.003 mol acid. M = 0.003/0.025 = 0.120 M.

500

N₂ + 3H₂ → 2NH₃. Liters of H₂ for 22.4 L NH₃ at STP?

22.4 L NH₃ = 1 mol. Needs 1.5 mol H₂ → 33.6 L.

500

Predict shape of NH₃ using VSEPR (Valence Shell Electron Pair Repulsion theory).

Trigonal pyramidal.

500

How is molarity used in pharmaceuticals?

Calculating drug solution concentrations.