400
A mixture of 0.100 mol of NO, 0.050 mol of H2, and 0.100 mol of H2O are placed in a 1.00-liter flask. The following equilibrium is established:
2 NO(g) + 2 H2(g) N2(g) + 2 H2O(g)
At equilibrium, [NO] = 0.070 M.
a) Calculate the equilibrium concentrations of H2, N2, and H2O.
b) Write an expression for K for this reaction.
c) Calculate K for this reaction.
d) At equilibrium, how will the concentrations of products compare to the concentrations of
reactants?
What is [NO] (M) [H2] (M) [N2] (M) [H2O] (M)
original 0.100 0.050 0 0.100
change - 0.030 - 0.030 +0.015 + 0.030
equilibrium 0.070 0.020 0.015 0.130