If our Chi-Square value is 17.87 and our df=6, do we have evidence to reject the null at a .05 alpha level?
Yes, reject the null. There is sufficient evidence to conclude that the alternative hypothesis is true.
If our Chi-Sq value is 30 and our df=15, do we have evidence to reject the null at a .01 alpha level?
No, fail to reject the null. There is not sufficient evidence to conclude that the alternative hypothesis is true.
We are testing whether our school has the same racial distribution as the country. Or Chi-Sq value is 17.8, and our p-value is .003. Write a complete conclusion based on an alpha level of .05.
Based on our low p-value of .003, we reject the null, and we have evidence to say that the racial distribution of our school differs from the racial distribution of the country as a whole.
When do you need to check for random and independent samples
Chi-Sq test for homogeneity
We ran a Chi-Sq test to see whether males or females scored differently on their AP Stat exams. We got a Chi-Sq of 3.72 and a p-value of .146. Write a complete conclusion based on a .05 alpha level.
Based on our high p-value, we fail to reject the null, and therefore we do not have evidence to conclude that males and females score differently on their AP Stat exams.
What is one reason for choosing a Chi-Sq test of Homogeneity instead of a Linear Regression T-Test?
If you have categorical data
How do you determine the expected counts for GOF test?
Take the sample size and multiply by the expected probabilities for each group.
In a Chi-Sq test to determine if there was a relationship between handedness (right- or left-handed) and eye color, the Chi-Sq value was 18.7 and the p-value was .043. Write a complete conclusion based on a .05 alpha level.
Based on our p-value, we reject the null, and we have evidence to conclude that there is an association between handedness and eye color.
How can you determine the difference between Chi-Sq test of Homogeneity and Chi-Sq test of Independence?
If any information is known before the survey (pre-determined groups), it is a Chi-Sq test of Homogeneity.