Equation work
Label all parts of the following equation with all appropriate information. (Words and Units) T = 2πr/v
T = Period (s) pi = (3.14) r = radius (m)
v = velocity (m/s)
where does the “2 pi r” come from in the equations?
The distance part of the period equation comes from the fact they we are going around a circle and that is the circumference (distance around the circle)
A car travels in a circular track of radius 50 m at a constant speed of 10 m/s. Find the period (T) of the motion.
T = 31.4s
Two objects have masses of 5.0 kg and 10.0 kg and are separated by a distance of 2.0 m. Find the gravitational force between them.
FG = 8.34×10−10 N
a = v^2/r
Label all parts of the following equation with all appropriate information. (Words and Units)
a = acceleration (m/s2) r = radius (m)
v = velocity (m/s)
When I shrink the radius, what happens to the circumference?
It gets smaller
A ball is swung in a horizontal circle with a radius of 2.0 m at a speed of 6.0 m/s. Find the centripetal acceleration (aᵣ).
a = 18 m/s2
Two spheres each have a mass of 20 kg and are 5.0 m apart. Find the gravitational force between them.
FG=1.07×10−9N
Label all parts of the following equation with all appropriate information. (Words and Units)
f = 1/T
f = frequency (Hz) T = Period (s)
What happens to the Force of attraction when I increase the radius by 2x?
The force is divided by 4
A 1200 kg car rounds a curve of radius 80 m at a speed of 20 m/s.
Find the centripetal force (Fₙ) acting on the car.
Fc = 6000 N
A 15 kg object is 3.0 m away from a 30 kg object.
a) Find the gravitational force between them
b) Find the acceleration of the 15 kg object using a=F/m
a) FG=3.34×10−9 N
b) a=2.23×10−10 m/s2
FG=G (m1 m2)/r^2
Label all parts of the following equation with all appropriate information. (Words and Units)
FG = Gravitational force (N) m = mass (kg)
r = radius (m)
What happens to the acceleration when I increase the radius of the circle?
The acceleration would decrease
A rotating ride has a radius of 10 m and completes one revolution every 5 seconds.
a) Find the frequency (f)
b) Find the speed (v) of a rider
f = 0.20 Hz
v = 12.6 m/s
Two objects experience a gravitational force of 2.0×10^−9 N. Their masses are 8.0 kg and 12.0 kg.
a) Solve for the distance (r) between them
b) If the distance is doubled, what happens to the force?
a) r≈1.79 m
b) Force becomes 5.0×10^−10 N (one-fourth the original)
Fc = mv^2/r
Label all parts of the following equation with all appropriate information. (Words and Units)
F = centripetal force (N) m = mass (kg)
r = radius (m) v = velocity (m/s)
what would need to happen if I wanted to increase the gravitational force? (there are 2 things that could happen, you need to get both)
Increase the mass
Decrease the radius
A 0.50 kg object moves in a circle of radius 1.5 m with a speed of 3.0 m/s.
a) Find the centripetal acceleration (aᵣ)
b) Use a=∑F/m to find the net force acting on the object
6.0 m/s2
3.0 N
Two identical masses are separated by a distance of 4.0 m and experience a force of 1.0×10−10 N. What will the new force be if the distance is reduced to 2.0 m?
Fnew=4.0×10−10 N