Equations
Newton's Second Law
EF = ma
What are the forces acting on a person going through a vertical loop that point to the center as they are passing the top of the loop?
Normal Force and Gravitational Force
On a certain planet the acceleration of gravity is equal to 6 m/s2. If the radius of the planet is doubled, while the mass is kept constant, what would be the new acceleration of gravity on the surface of the planet?
1.5 m/s^2
Centripetal Acceleration
a = v^2/r
A roller coaster ride is determined to be too dangerous because the normal force passengers experience while going through loops is too great. How can they lower that force? HINT: THINK ABOUT THE FORMULA!
Increase Radius
Decrease velocity
Centripetal velocity
2pi*r/T
How does Newton’s first law relate to circular motion?
The velocity of an object in tangential to the circular path. Once centripetal force is released, it wants to move in a straight line from the release point
A car is traveling through a traffic circle that is not banked. If the car has a mass of 1100
kg, the coefficient of friction is .8, and the radius of the turn is 30 m, how fast can a car
safely go through the turn?
15.3 m/s^2
Law of Universal Gravitational
F = G*M1*M2/r^2
Explain the relationship between the radius and the force of gravity, and the masses and
the force of gravity for Newton’s law of universal gravitation.
Increase Radius -> Decrease FG
Increase Mass -> Increase FG
Derive the equation for the summation of CENTRIPETAL FORCES acting on a pilot of a plane going around a vertical loop
EFy = ma
Fg + Fn = mv^2/r
Draw the orbit for the moon going around the Earth. Draw and label arrows showing
the direction of the velocity, the acceleration, and the net force for the moon.
On white board :)
A fuzzy dice is hanging from a mirror. If the car goes through a turn of 100 m radius at
20 m/s. Find the value for the angle. (Start off
finding the horizontal and vertical components of tension. And the mass of the fuzzy
dice is .1 kg.
22.2 degrees