Exponentials
Logarithmic
Ln
Compounding interest
Inverses
100

Which are exponential functions?

3x      x5      -2     xx

3x

100

Solve without a calculator

log2(8)=y

y=3

100

Solve without a calculator

ln(e3)=y

y=3

100

What is the n value for compounding:

Monthly?

Yearly?

Quarterly?

Monthly=12

Yearly=1

Quarterly=4

100

What is your first step to finding an inverse?

Switch the x and y in the function

200

Solve without a calculator

53=5x

x=3

200

Solve without a calculator

log4x=2

x=16

200

Simplify using log/ln rules

ln(x4)

4ln(x)

200

Set up the equation to measure the amount of money in an account over time if you invest $5000 compounded monthly at a 7% interest rate

A=5000(1+.07/12)^(12t)

200

What is the inverse of:

y=2x+4

y=(x-4)/2

300

2x=16

x=4

300

Solve without a calculator

log(x)=3

x=103 = 1000

300

Simplify using log/ln rules

ln(x/5)

ln(x)-ln(5)

300

Find the amount of money accumulated if you invest $1500 at a 7% interest rate for 6 years compounded annually.

$2251.10

300

What is the inverse of:

y=2x^4-3

y=root(4)((x+3)/2

400

(1/2)^x=1/8

x=3

400

Solve without a calculator

logb(36)=2

b=6

400

Put into condensed form

2ln(x)-4ln(2)

ln(x^2/2^4)

400

Compound interest Yearly for 5 years on $10,000 at 20% interest. Suppose I deposit this money into an interest bearing account in 2012 and want to know how much it will be worth at the end of 2017. How much would it be worth?

$24,883

400

Verify the following are inverses:

y=5x-3

y=(x+3)/5

y=5((x+3)/5)-3

(x+3)-3

x

500

Solve without a calculator

ex=5

x=ln(5)

500

Solve without a calculator

logx+4(64)=2

x=4

500

Simplify 

ln(e^2/2)

ln(e^2)-ln(2)

2ln(e)-ln(2)

2-ln(2)

500

If someone invests $15,000 into an account with a 8% interest rate compounded monthly, how long will it be until the account contains $45,000?

13.78 years

500

Verify the following are inverses:

y=(x-2)^3+4

y=root(3)(x-4)+2

((root(3)(x-4)+2)-2)^3+4

(root(3)(x-4))^3+4

(x-4)+4

x